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denis-greek [22]
3 years ago
15

Use cross multiplication to solve the equation

Mathematics
1 answer:
Charra [1.4K]3 years ago
4 0

Answer:

wheres the equation??

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Will give brainliest please answer
lubasha [3.4K]

Answer:

1 to column a

2 to column b

3 to collumn a

4 to column a

5 to column b

put me brainliest please!!!

Step-by-step explanation:

4 0
3 years ago
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The figure shows three right triangles. Triangles PQS, QRS, and PRQ are similar. Theorem: If two triangles are similar, the corr
stepladder [879]

Answer:

C. Segment PR ⋅ segment PS = 16

    Segment PR ⋅ segment SR = 81

Step-by-step explanation:

My teacher went over this question with me not even like 5 minutes ago

4 0
3 years ago
What is the maximum value that the graph of y = cos x assumes?
Scorpion4ik [409]
The maximum value of that graph is 1 and we can prove this by means of this graph:
http://assets.openstudy.com/updates/attachments/4fe27e44e4b06e92b87169f6-syderitic-1340243754047-unt...

I hope this one works for you
8 0
3 years ago
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Plz guys help me with this question
Tema [17]

Answer:

Madhu diposited Rs 20000 in a bank,

Rate=10% per annum compounded half yearly,

Time=

2

3

years.

We know that,

               Total amount= Principle+CI

For interest compounded half yearly,

Total amount =P(1+(

200

R

​ ))

2n

=20000(1+(

200

10

))

2×

2

3

=

200×200×200

20000×210×210×210​

=22050

Interest=Amount−Principle

=22050−20000

=2050 Rs

Step-by-step explanation:

i hope it helps

7 0
3 years ago
Find m<br> ∠<br> J<br> L<br> K<br> ∠JLK.
seraphim [82]

Answer:

m∠JLK° = 62°

Step-by-step explanation:

∠JLK = ∠KJL

SO

56°+2(∠JLK)° = 180°

2(∠JLK)° = 180-56

2(∠JLK)° = 124

∠JLK° = 62°

so m∠JLK° = 62°

7 0
3 years ago
Read 2 more answers
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