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Kay [80]
3 years ago
13

A sample of C3H8 has 6.96 × 1024 H atoms. How many carbon atoms does the sample contain?

Chemistry
1 answer:
Anastaziya [24]3 years ago
4 0
A sample has 3.28 X 10^24 h atoms
 
 so first we will find the moles of Hydrogen <span>by putting values in formula 
that is
. moles </span>= no. of atoms/ Avogadro's no (NA) moles
 = 5.446 we got this
<span> now the ratio of Carbon and Hydrogen is: C = H </span>
<span>      3 = 8 </span>
now multiply it with the moles
      3/8 * 5.466 = 5.466 2.05 is the moles of C
. now:find the no of C atoms by this
<span> = moles X NA </span>
 = 2.05 X 6.022 X 10^23
 = 1.27 X10^2
now will find the mass of sampl:
  so One mole of C3H8 = 3 moles of C 1/3 * 2.05 = 2.05 moles of C
<span> 0.68 moles of C3H8. </span>
 now the mass of C3H8 = moles X molar mass mass of C3H8
 which is = 0.68 X 44 =
<span> 30.2 grams of C3H8</span>
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Standard enthalpy of formation of carbon dioxide= \Delta H_{f,CO_2}=-393.5 kJ/mol

Standard enthalpy of formation of water = \Delta H_{f,H_2O}=-285.8 kJ/mol

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=8\times \Delta H_{f,CO_2} +10\times \Delta H_{f,H_2O}+2\times \Delta H_{f,N_2} - (4\times \Delta H_{f,gly}+9\times \Delta H_{f,O_2})

-3896 kJ/mol=8\times (-393.5 kJ/mol)+ 10\times (-285.8 kJ/mol)+0 - (4\times \Delta H_{f,gly} +0)

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4\times \Delta H_{f,gly}=8\times (-393.5 kJ/mol)+ 10\times (-285.8 kJ/mol)+ 3896 kJ/mol

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