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Ksenya-84 [330]
3 years ago
12

This is one of the basic needs for survival. It is a component of an organism's living space and it provides protection from the

environmental elements, a place to breed, and sleep or hibernate.
Chemistry
2 answers:
Nitella [24]3 years ago
7 0

the answer is shelter

Y_Kistochka [10]3 years ago
3 0
Rhffffffffffffffffffffffffffffffffffffffsdfjccguyc ftu7y7y7y7y7yu c                                                                         
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The___ step in balancing a chemical equation is to take inventory or count atoms on the reactant & the product side.
Kazeer [188]

Answer: The first step in balancing a chemical equation is to take inventory or count atoms on the reactant & the product side.

Explanation:

***If you found my answer helpful, please give me the brainliest. :) ***

6 0
2 years ago
Help asap. picture below.
Rashid [163]

Answer:

C. If a solar cell breaks, it releases chemicals and can harm humans.

Explanation:

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3 0
3 years ago
How many moles are there in 24.0 grams of H2O
Nata [24]

Answer:So, one mole of water has a mass of 16 +1+1 = 18 grams. So, if one mole has a mass of 18 grams, 25 grams would have a mass of 25 grams/ 18 grams per mole or 1.39 moles

6 0
3 years ago
Read 2 more answers
What is the acceleration object velocity of +25m/s to rest in 5.0 s
Irina-Kira [14]

The average acceleration is -5.0 m·s⁻².

The formula for acceleration (<em>a</em>) is

a = \frac{v_{f}- v_{i}}{t}

v_{f} = 25 m·s⁻¹;  v_{i} = 0; t = 5.0 s

∴ a = \frac{0-25}{5.0} = -5.0 m·s⁻²

The negative sign tells you that the object is <em>slowing down</em>, i.e., it is <em>decelerating</em>.


4 0
3 years ago
Consider a solution containing .100 M fluoride ions and .126M hydrogen fluoride. The concentration of fluoride ions after the ad
S_A_V [24]
Given:

Concentration of Fluoride ions = 0.100 M
Concentration of Hydrogen Fluoride = 0.126 M

Asked: Concentration of fluoride ions after the addition of 5ml of 0.0100 M HCl to 25 mL of the solution

Assume: 50:50 ratio of fluoride ions and HF

12.5ml*0.1mol/L *1L/1000mL + 12.5*0.126mol/L * 1L/1000mL = 2.825x10^-3 moles F-

5ml * 0.01 mol/L *1L/1000mL = 5x10^-5 moles

Assume: Volume additive

Final concentration = 2.825x10^-3 + 5x10^-5 moles/ 30 ml * 1000ml/L =0.0958 M
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3 0
3 years ago
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