Question

Find the solution(s) to 2x^2-7x+3=0 check all that apply

Answer 1

Answer:

Step-by-step explanation:

2x^2-7x+3=0

Using mid term break method

2x^2-6x-x+3=0

2x(x-3)-1(x-3)=0. took common

(2x-1)(x-3)=0

So Either,

2x-1=0 OR x-3=0

X=1/2 OR x-3=0

Answer 2

Answer:

see explanation

Step-by-step explanation:

Given

2x² - 7x + 3 = 0

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 × 3 = 6 and sum = - 7

The factors are - 6 and - 1

Use these factors to split the x- term

2x² - 6x - x + 3 = 0 ( factor the first/second and third/fourth terms )

2x(x - 3) - 1(x - 3) = 0 ← factor out (x - 3) from each term

(x - 3)(2x - 1) = 0

Equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = $\frac{1}{2}$