A person holding a lunch bag is moving upward in a hot air balloon at a constant speed of 7.7 m/s . When the balloon is 21 m abo
ve the ground, she accidentally releases the bag. Part A What is the speed of the bag just before it reaches the ground
1 answer:
Answer:
The speed of the bag just before it reaches the ground is 21.71 m/s.
Explanation:
The speed of the bag can be found using the following equation:
Where:
is the final speed =?
is the initial speed = 7.7 m/s
g: is the gravity = 9.81 m/s²
y: is the height = 21 m
Therefore, the speed of the bag just before it reaches the ground is 21.71 m/s.
I hope it helps you!
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Answer:
P_2 = 62.69 psi
Explanation:
given,
P₁ = 70 psia T₁ = 55° F = (55 + 459.67) R
P₂ = ? T₂ = 115° F = (115 + 459.67) R
we know,
p = ρ RT
ρ is the density which is constant
R is also constant
now,
P_2 = 62.69 psi
Hence, the increase in Pressure is equal to P_2 = 62.69 psi
Answer:
having only magnitude, not direction
Explanation:
the 2nd one because it says no direction
It is an intensive property as it varies with time and position within the system.
I showed my working in the images above. if you have any questions please feel free to ask