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tiny-mole [99]
3 years ago
5

Mostly question three, but I'm not sure how to work out the speed. Thank you!

Physics
2 answers:
telo118 [61]3 years ago
8 0
The speed of sound follows the same rules, just like any other speed, if the acceleration is zero.

distance = speed * time

distance = 2m
speed = 333m/s

Solve for time t.
Finger [1]3 years ago
4 0
From this question we can obtain the following equestion:
T=displacement ÷ velocity (2m ÷ 333m/s) equal to 6×10^-3
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3. A sample of argon of mass 6.56 g occupies 18.5 dm? at 305 K. (a) Calculate the work done when the gas expands isothermally ag
aleksandr82 [10.1K]

Answer:

(a) W=-19.25J

(b) W=-52.8J

Explanation:

Hello.

(a) In this case, since the initial volume is 18.5 dm³ and the final volume is 21 dm³ (18.5 +2.5), we can compute the work at constant pressure as shown below:

W=-P\Delta V=-7.7kPa*\frac{1000Pa}{1kPa} (21dm^3-18.5dm^3)*\frac{1m^3}{1000dm^3}\\ \\W=-19.25J

Which is negative as it expands against the given pressure.

(b) Moreover, of the process is carried out reversibly, the pressure can change, therefore, we need to compute the work via:

W=nRTln(\frac{V_1}{V_2} )

Whereas the moles are computed from the given mass of argon:

n=6.56g*\frac{1mol}{39.95g}=0.164mol

Thus, the work is:

W=0.164mol*8.314\frac{J}{mol*K} *305Kln(\frac{18.5dm^3}{21dm^3} )\\\\W=-52.8J

Regards.

4 0
3 years ago
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