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3 years ago

Mostly question three, but I'm not sure how to work out the speed. Thank you!

Physics

2 answers:

telo118 [61]3 years ago

8 0

The speed of sound follows the same rules, just like any other speed, if the acceleration is zero.

distance = speed * time

distance = 2m
speed = 333m/s

Solve for time t.

Finger [1]3 years ago

4 0

From this question we can obtain the following equestion:
T=displacement ÷ velocity (2m ÷ 333m/s) equal to 6×10^-3

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When three people with a total mass of 2.00 x 102 kg step into their 1.200 x 103 kg car, the car’s

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Answer:

$k = 457333.3 N/m$

$x_a =0.09\ m$

Explanation:

From the question we are told that

The total mass of three people is $M = 2.00*10^{2} \ kg$

The mass of the car is $m_c = 1.200 *10^{3} \ kg$

The compression of the car spring is $x = 3 \ cm = 0.03 \ m$

Generally the spring constant is mathematically represented as

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Here F is the force exerted by the mass of three people and that of the car , this is mathematically represented as

=> $F = (M +m_c) *g$

=> $F = ([2.0*10^{2} ]+[ 1.200*10^{3}]) * 9.8$

=> $F = 13720 \ N$

$k = \frac{13720}{0.03}$

=> $k = 457333.3 N/m$

Generally if the mass which the car is loaded with is $m = 3.00*10^{2} \ kg$

Then the force experienced by the spring is

=> $F_a = (m +m_c) *g$

=> $F_a = (3.00*10^{3} + 1.200 *10^{3}) * 9.8$

=> $F_a = 41160 \ N$

Generally from the above formula the compression is

$x_a = \frac{F_a}{k}$

=> $x_a = \frac{41160}{457333.3}$

=> $x_a =0.09\ m$

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