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Blababa [14]
3 years ago
12

Describe a situation where an object would have potential energy transformed into kinetic energy?

Physics
2 answers:
tigry1 [53]3 years ago
6 0

Answer:

When an object falls, its gravitational potential energy is changed to kinetic energy.

Explanation:

Alinara [238K]3 years ago
5 0
A prime example is a rollercoaster. As the rollercoaster goes up the hill it has a ton of potential energy and as it falls it is turned into kinetic energy which keeps the coaster moving.
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Suppose that you are holding a cup of coffee in your hand identify all forces on the cup and reaction to each force
Stels [109]

Answer:

Newton's third law.

Explanation:

•your hand of holding UP/DOWN the cup has a reaction with force

•Coffee inside the cup is pushing outward to the edges of the cup

•The cup is pushing inward onto the coffee

"His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A."

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How do the causes of surface and deepwater currents differ
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The temperature is colder, and the water pressure is higher.

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3 years ago
A 0.272-kg volleyball approaches a player horizontally with a speed of 12.6 m/s. The player strikes the ball with her fist and c
Nady [450]

(a) +9.30 kg m/s

The impulse exerted on an object is equal to its change in momentum:

I= \Delta p = m \Delta v = m (v-u)

where

m is the mass of the object

\Delta v is the change in velocity of the object, with

v = final velocity

u = initial velocity

For the volleyball in this problem:

m = 0.272 kg

u = -12.6 m/s

v = +21.6 m/s

So the impulse is

I=(0.272 kg)(21.6 m/s - (-12.6 m/s)=+9.30 kg m/s

(b) 155 N

The impulse can also be rewritten as

I=F \Delta t

where

F is the force exerted on the volleyball (which is equal and opposite to the force exerted by the volleyball on the fist of the player, according to Newton's third law)

\Delta t is the duration of the collision

In this situation, we have

\Delta t = 0.06 s

So we can re-arrange the equation to find the magnitude of the average force:

F=\frac{I}{\Delta t}=\frac{9.30 kg m/s}{0.06 s}=155 N

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3 years ago
I need help doing this i don’t understand what to do
Hatshy [7]

Answer:

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Explanation:

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