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serg [7]
3 years ago
12

Use your observations of the circuit construction simulation experiment and your course notes to answer the following questions.

Which statement is true? When two resistors are connected in series, there is less total current in the circuit than if the two resistors were connected in parallel. When two resistors are connected in parallel, there is less total current in the circuit than if the two resistors were connected in series. The total current is the same regardless of if the two resistors are connected in series or in parallel.
Physics
2 answers:
Shkiper50 [21]3 years ago
8 0

Answer:

When two resistors are connected in series, there is less total current in the circuit than if the two resistors were connected in parallel.

Explanation:

When two or more resistors are connected in series then total resistance is given as

R = R_1 + R_2

while if two or more resistors are connected in parallel then total resistance is given as

\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}

so here we can say that net resistance would be less in the circuit if resistors are connected in parallel

so here we can say that

When two resistors are connected in series, there is less total current in the circuit than if the two resistors were connected in parallel.

Stels [109]3 years ago
3 0
<span>I didn't do the circuit construction simulation experiment, and
I don't have any course notes.  Both of those were YOUR job. 

But I'm still going to take your points.  I'll try to answer the question
based on what I know, and you'll just have to decide whether you
trust me, even though I never had any contact with your class or
anything that happened there.

I believe that when two resistors are connected in series,
there is less total current in the circuit than if the two resistors
were connected in parallel.  That's the first choice.</span>
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To solve this problem, we will start by defining each of the variables given and proceed to find the modulus of elasticity of the object. We will calculate the deformation per unit of elastic volume and finally we will calculate the net energy of the system. Let's start defining the variables

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S_{el} = 414Mpa

Yield Strain of the Specimen

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U'_{el} = 414kN\cdot m/m^3

Considering that the net strain energy of the sample is

U_{el} = U_{el}' \cdot (\text{Volume of sample})

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Let z=f(x,y) = 15 - 5x - 3y. Then the area of the plane over T is

\displaystyle \iint_T dA = \iint_T \sqrt{1 + \left(\frac{\partial f}{\partial x}\right)^2 + \left(\frac{\partial f}{\partial y}\right)^2} \, dx \, dy

We have

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E=\dfrac{kq}{r^2}

Put the value into the formula

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