Formation of ammonia by nitrogen and hydrogen is habers process wher 28g N2 results in formation of 34g NH3
so 35g N2 will form 34*35/28=42.5g NH3 where it given that reaction takes place in excess of H2
N2+3H2 gives 2NH3

4 0

2 years ago

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Help please please please please

Rom4ik [11]

Answer:

D. 18.7 grams

Explanation:

The coefficients are the key.

Create a proportion with them, and the molar mass, and then solve for x:

$\frac{2}{3} = \frac{x}{28} \\ 3x = 2(28) \\ 3x = 56 \\ x = 18.666... = 18.7$

7 0

3 years ago

Hemoglobin in your blood does not use elemental iron. It uses iron in the form of Fe2+(aq).

valina [46]

Explanation:

Balanced chemical reaction equation will be as follows.

$2Fe^{2+}(aq) + 2H^{+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + H_{2}(g)$

In human body, the neutral iron changes into $Fe^{2+}$ (aq) cation. There will be an oxidation-half reaction and a reduction-half reaction. Equations for this reaction are as follows.

Oxidation: 2Fe^{2+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + 2e^{-}[/tex] .... (1)

Reduction: $2H^{+}(aq) + 2e^{-} \rightleftharpoons H_{2}(g)$ ...... (2)

On adding both equation (1) and (2), the overall reaction equation will be as follows.

$2Fe^{2+}(aq) + 2H^{+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + H_{2}(g)$

Therefore, neutral iron is a part of Heme - b group of Hemoglobin and in an aqueous solution it dissolutes as a part of Heme group. Hence, then it becomes an $Fe^{2+}$ cation.

3 0

2 years ago