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Katyanochek1 [597]
2 years ago
12

No links.

Chemistry
1 answer:
Gennadij [26K]2 years ago
5 0

Explanation:

first find the value of Ph

from Ph= -log[H+]

ph=-log[1.7x10^-8]=7.769

find Poh from 14=ph+poh

14=7.769+poh

Poh=6.231 part a

for part b the same as part a from the above procedure

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¿Cuántos moles de C3H8 contienen 9.25 x 10^24 moléculas?
Igoryamba

Answer:

\large \boxed{\text{e. 15.4 mol C$_{3}$H}_{8}}

Explanation:\text{Moles of propane} = 9.25 \times 10^{24}\text{ molecules} \times \dfrac{\text{1 mol }}{6.022 \times\ 10^{23} \text{molecules}} = \textbf{15.4 mol}

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How much energy is required to convert 100.0 g of water completely<br> to steam?
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Answer:

<u>225.6 kJ</u>, <em>assuming the water is already at 100 °C</em>

Explanation:

The correct answer to this question will depend on the initial temperature of the water to which heat is added to produce steam.  Energy is required to raise the water temperature to 100°C.  At that point, an energy of vaporization is needed to convert liquid water at 100 °C to water vapor at 100°C.  The heat of vaporization for water is 2256.4 kJ/kg.  The energy required to bring 100g of water from a lower temperature to 100°C is calculated at 4.186 J/g°C.  We don't know the starting temperature, so this step cannot be calculated.

<em><u>Assuming</u></em> that we are already at 100 °C, we can calculate the heat required for vaporization:

(100.0g)(1000.0g/1 kg)(2256.4 kJ/kg) = 225.6 kJ for 100 grams water.

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A sample of carbon monoxide gas is initially in a 5858 mL container. The gas is then moved to 3.29 L container at a temperature
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For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ
Komok [63]

Answer:

Check the explanation

Explanation:

Answer – Given, H_3PO_4 acid and there are three Ka values

K_{a1}=6.9x10^8, K_{a2} = 6.2X10^8, and K_{a3}=4.8X10^{13}

The transformation of H_2PO_4- (aq) to HPO_4^2-(aq)is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

Mass of KH2PO4 = 22.0 g , mass of Na2HPO4 = 32.0 g , volume = 1.00 L

First we need to calculate moles of each

Moles of KH2PO4 = 22.0 g / 136.08 g.mol-1

                             = 0.162 moles

Moles of Na2HPO4 = 32.0 g /141.96 g.mol-1

                             = 0.225 moles

[H2PO4-] = 0.162 moles / 1.00 L = 0.162 M

[HPO42-] = 0.225 moles / 1.00 L = 0.225 M

Now we need to calculate the pKa2

pKa2 = -log Ka

       = -log 6.2x10-8

       = 7.21

We know Henderson-Hasselbalch equation

pH = pKa + log [conjugate base] / [acid]

pH = 7.21 + log 0.225 / 0.162

     = 7.35

The pH of a buffer solution obtained by dissolving 22.0 g of KH2PO4 and 32.0 g of Na2HPO4 in water and then diluting to 1.00 L is 7.35

6 0
3 years ago
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