The atomic weight reported in the periodic table of elements for Carbon is the average weight of all the known isotopes of Carbon occurring naturally. There are 3: Carbon-12, Carbon-13 and Carbon-14. The numbers represent the mass numbers, or the sum of neutrons and protons in the nucleus. Each of the individual masses are multiplied with their individual percentage abundances. Then, when you add them up, it will yield the average atomic weight equal to 12.011 amu or grams/mole C.
It looks like A is balanced
Answer:
The movement of electrons is kinetic energy, capable of producing electrical energy (option B).
Explanation:
An electron is a mobile subatomic particle, located outside the atom and forming elliptical orbits, unlike protons and neutrons. In addition, each electron has a negative charge.
<u>The energy on which the movement of the electrons depends is kinetic energy, which promotes this movement</u>. The interaction between the negative charges of the electrons and the positive charge of the protons produces electrical energy.
<em>The other options are not correct because the charge energy, electric energy and magnetic energy are consequences of the activity of the subatomic particles of the atom.</em>
Mass measures the amount of matter in an object
Explanation:
(w/w) % : The percentage mass or fraction of mass of the of solute present in total mass of the solution.

1) 100 g of 0.500% (w/w) NaI
Mass of solution = 100 g
Mass of solute = x
Required w/w % of solution = 0.500%


0.500 grams of solute needed to make 100 g of 0.500% (w/w) NaI.
2) 250 g of 0.500% (w/w) NaBr
Mass of solution = 250 g
Mass of solute = x
Required w/w % of solution = 0.500%


1.25 grams of solute needed to make 250 g of 0.500% (w/w) NaBr
3) 500 g of 1.25% (w/w) glucose
Mass of solution = 500 g
Mass of solute = x
Required w/w % of solution = 1.25%


6.25 grams of solute needed to make 500 g of 1.25% (w/w) (glucose)
4) 750 g of 2.00% (w/w) sulfuric acid.
Mass of solution = 750 g
Mass of solute = x
Required w/w % of solution = 2.00%


15.0 grams of solute needed to make 750 g of 2.00% (w/w) sulfuric acid.