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Softa [21]
2 years ago
12

Why are there groups, in the periodic table?

Chemistry
2 answers:
Rasek [7]2 years ago
7 0
Groups help organize the elements. Elements of the same group have similar chemical qualities. So looking at an element’s group on the periodic table can help you identify some of it’s characteristics such it’s as reactivity with other elements or of it’s a good conductor.
zepelin [54]2 years ago
6 0
To classify the elements and make them easier to understand
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Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu
Svet_ta [14]

Answer:

V_1=23.3~mL

Explanation:

In this case, we have a dilution problem. We have to remember that in the dilution procedure we go from a solution with higher concentration to a solution with lesser concentration. Therefore we have to start with the dilution equation:

C_1*V_1=C_2*V_2

Now we can identify the variables:

C_1=~1.475_M

V_1=~?

C_2=~0.1374_M

V_2=~250.0~mL

If we plug all the values into the equation:

1.475_M*V_1=0.1374_M*250.0~mL

And we solve for V_1:

V_1=\frac{0.1374_M*250.0~mL}{1.475_M}

V_1=23.3~mL

I hope it helps!

8 0
3 years ago
How many electrons would be found in the Ion who’s symbol is I-
Vesnalui [34]

Answer:

54

Explanation:

Given symbol of the element:

                   I⁻

Number of electrons found in an ion with the symbol:

  This is a iodine ion:

         For an atom of iodine:

                   Electrons  = 53

                   Protons  = 53

                   Neutrons  = 74

An ion of iodine is one that has lost or gained electrons.

For this one, we have a negatively charged ion which implies that the number of electrons is 1 more than that of the protons.

  So, number of electrons  = 53 + 1  = 54

The number of electrons in this ion is 54

6 0
2 years ago
A sulfuric acid solution containing 571.3 g of h2so4 per liter of aqueous solution has a density of 1.329 g/cm3. Part a calculat
loris [4]

Mass percentage of a solution is the amount of solute present in 100 g of the solution.

Given data:

Mass of solute H2SO4 = 571.3 g

Volume of the solution = 1 lit = 1000 ml

Density of solution = 1.329 g/cm3 = 1.329 g/ml

Calculations:

Mass of the given volume of solution = 1.329 g * 1000 ml/1 ml = 1329 g

Therefore we have:

571.3 g of H2SO4 in 1329 g of the solution

Hence, the amount of H2SO4 in 100 g of solution= 571.3 *100/1329 = 42.987

Mass percentage of H2SO4 (%w/w) is 42.99 %

3 0
3 years ago
PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!!
Marina CMI [18]

Answer:

C

Explanation:

It afffects changes in pressure and temperature not melting and boiling points

5 0
2 years ago
What agent of weathering is acid precipitation?
Alona [7]
It would be considered acid rain in the sense of dew fall
3 0
3 years ago
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