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3 years ago

One of the important waste products of photosynthesis is oxygen gas. Where does this oxygen gas come from?

Physics

2 answers:

Pani-rosa [81]3 years ago

8 0

Answer:

Explanation:

Equation of photosynthesis:

6CO2(g) + 6H2O(l) --> C6H12O6(s) + 6O2(g)

From the above equation, on the RHS, The oxygen during photosynthesis comes from split water molecules. During photosynthesis, the plant absorbs water and carbon dioxide. After the absorption, the water molecules are disassembled or broken down to extract electrons and protons in the presence of ultraviolet light and converted into simple sugar and oxygen.

Equation of the water breakdown:

2H2O --> O2 + 4H+

chubhunter [2.5K]3 years ago

5 0

Answer:

End product of photosynthesis.

Explanation:

Photosynthesis is a process that plants undergo in the manufacture of their food. This is done in the presence of sunlight which is trapped by their coloring pigment called chlorophyll and reactants such as Carbon dioxide and Water.

6CO2+6H2O= C6H12O6+ 6O2

The oxygen gas which is a waste product of photosynthesis is released into the atmosphere and used by animals in respiration.

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3 years ago

A spring has a constant k= 10.32 N/m and is hung vertically. A 0.400kg mass is suspended from the spring. What is the displaceme

alukav5142 [94]

Answer:

displacement (x) = 0.003798 meters

Explanation:

from the fact that the string is hung vertically we can deduce that:

Total force acting on the mass = Fs (by spring) + Fg (by gravity)

where

Fs = k*x , x is the displacement..

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then:

Ftot = m*a, but a = 0 m/(s^2) because the mass becames stationary.

Ftot = 0

Fs + Fg = 0

by direction, take down as negative.

Fs - Fg = 0

k*x = m*g

x = m*g/k = [(0.400)(9.8)]/(10.32)

= 0.3798 meters

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3 years ago

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Elena-2011 [213]

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3 years ago

Water is considered to be

Natalka [10]

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3 years ago

A mass attached to a spring oscillates with a period of 22 sec. After 22 kg are added, the period becomes 33 sec. Assuming that

polet [3.4K]

Answer:

Mass of 17.854 kg is only attached to the spring

Explanation:

We have given time period in first case is 22 sec

Let initially mass is m

After 22 kg are added the period becomes 33 sec

Time period of spring mass system is

$T=2\pi \sqrt{\frac{m}{k}}$ , here m is mass and k is spring constant

From the relation we can see that

$\frac{T_1}{T_2}=\sqrt{\frac{m}{m+22}}$

$\frac{22}{33}=\sqrt{\frac{m}{m+22}}$

Squaring both side

$0.444={\frac{m}{m+22}}$

$0.444m+9.777=m$

m = 17.584 kg

So mass of 17.854 kg is only attached to the spring

7 0

3 years ago