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3 years ago

a person runs 27.0km west then turns around and runs 13.0km east what's the distance and displacement ?

Physics

1 answer:

Alexxandr [17]3 years ago

7 0

Answer:

See below

Explanation:

Distance = 27 + 13 = 40 km

Displacement = 27 - 13 = 14 km

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Korvikt [17]

60km/hr..

I think so....

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3 years ago

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Suppose a person whose mass is m is being held up against the wall with a constant tangential velocity v greater than the minimu

Likurg_2 [28]

Answer:

Explanation:

The man is moving on a circular path . The reaction of wall is providing centripetal force .so

R = mv² / r

Frictional force = μR where μ is coefficient of friction

= μ x mv² / r

Frictional force = μ x mv² / r

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3 years ago

Block A, with mass mA, is initially at rest on a horizontal floor. Block B, with mass mB, is initially at rest on the horizontal

nexus9112 [7]

Answer:

(E) μs(mA +mB)g

Explanation:

We can apply for mB:

∑ Fx = mB*a (→)

⇒ Ffriction = mB*a ⇒ a = Ffriction / mB = μs*N / mB

⇒ a = μs*(mB*g) / mB ⇒ a = μs*g (acceleration of the system)

Now, for mA we have

∑ Fx = mA*a (→)

F - Ffriction = mA*a ⇒ F = mA*a + Ffriction

⇒ F = mA*(μs*g) + μs*(mB*g) ⇒ F = μs*g*(mA + mB)

We must know that the friction acts only between the two blocks

8 0

3 years ago

A mass weighing 4 lb stretches a spring 2 in. Suppose that the mass is given an additional 6-in displacement in the positive dir

givi [52]

Answer:

$\frac{1}{8} y'' + 2y' + 24y=0$

Explanation:

The standard form of the 2nd order differential equation governing the motion of mass-spring system is given by

$my'' + \zeta y' + ky=0$

Where m is the mass, ζ is the damping constant, and k is the spring constant.

The spring constant k can be found by

$w - kL=0$

$mg - kL=0$

$4 - k\frac{1}{6}=0$

$k = 4\times 6 =24$

The damping constant can be found by

$F = -\zeta y'$

$6 = 3\zeta$

$\zeta = \frac{6}{3} = 2$

Finally, the mass m can be found by

$w = 4$

$mg=4$

$m = \frac{4}{g}$

Where g is approximately 32 ft/s²

$m = \frac{4}{32} = \frac{1}{8}$

Therefore, the required differential equation is

$my'' + \zeta y' + ky=0$

$\frac{1}{8} y'' + 2y' + 24y=0$

The initial position is

$y(0) = \frac{1}{2}$

The initial velocity is

$y'(0) = 0$

6 0

3 years ago

During a race, a sprinter accelerated 1.8 m/s 2 in 2.5 seconds.How many meters per second did the sprint increase with this amou

trasher [3.6K]

During a race, a sprinter accelerated 1.8 m/s 2 in 2.5 seconds. The sprint increase with this amount of acceleration by 4.5 m/s.

<h3>What is acceleration?</h3>

Acceleration is the time rate of change of velocity.

Acceleration a = velocity v / time t

1.8 = v/2.5

v = 4.5 m/s

The sprint increase with this amount of acceleration by 4.5 m/s.

Learn more about acceleration.

brainly.com/question/12550364

#SPJ1

3 0

2 years ago