<span>x=1.9+2.5t+3.7<span>t2</span></span>
<span>V=2.5−3.7t</span>
V=0 when it stops
0=2.5-7.4t
t=0.3378
a) <span>x=1.9+2.5t+3.7<span>t2</span></span> (t=0.3378)
x=3.1167m
b) <span>V=2.5−3.7t</span><span>
(t=0)
V=2.5 but because it's returning here velocity is -2.5</span>
