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Leto [7]
3 years ago
13

If distance between two charges increased 5 times then force between them

Physics
1 answer:
Marrrta [24]3 years ago
4 0

decreased 5 times

Explanation: if the force increases 5 times between them would decrease 5 times

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Four blocks of weights are required using which any body whose weight is between 1kg and 40 kg can be weighed. Find the four wei
Vikentia [17]

Answer:

The weights are 1 kg, 3kg, 9kg and 27kg.

Explanation:

The weights are 1 kg, 3kg, 9kg and 27kg.

1+3+9+27= 40

27+9+3= 39

27+9+3-1=38

27+9+1=37

27+9=36

27+9-1=35

27+9+1-3=34

27+9-3=33

27+9-3-1=32

27+3+1=31

27+3=30

27+3-1=29

27+1=28

27

27-1=26

27+1-3=25

27-3=24

27-3-1=23

27+3+1-9=22

27+3-9=21

27+3-9-1=20

Like this all the weights from 1 to 40 kg can be made using 1,3,9 and 27 kg.

6 0
3 years ago
A man in a strength competition pulls an 18-wheel truck 3.10 m in 20.5 s. There is a cable that is attached to his body that exe
larisa [96]

Answer:

114.32195122 but Round your answer to three significant figures.) is 114

Explanation:

Just took the test

4 0
3 years ago
An object of mass 20 kg is raised vertically through a distance of 8 m above ground level. If g = 10 m/s2, what is the gravitati
IgorC [24]

2400joules

Explanation:

P.E

m= 20kg h=8m g=10m

P.E= 20×8×10

=2400joules

6 0
3 years ago
PLEASE HELP ME!! What is the difference between direct current and alternating current?
Paha777 [63]
In a direct current the electric charge flows in one direction.
in an alternating the electric charge changes in its direction periodically.
6 0
4 years ago
An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only
Gnesinka [82]

Answer:

15.75 m/s

Explanation:

v = Velocity of the combined mass of astronaut and tools = 1.8 m/s

m_1 = Mass of astronaut = 124 kg

m_2 = Mass of tools = 16 kg

v_1 = Velocity of astronaut = 0

v_2 = Velocity of tools

As linear momentum is conserved

m_1v_1 + m_2v_2 =(m_1 + m_2)v\\\Rightarrow v_2=\frac{(m_1 + m_2)v-m_1v_1}{m_2}\\\Rightarrow v_2=\frac{(124+16)\times 1.8-124\times 0}{16}\\\Rightarrow v_2=15.75\ m/s

The velocity of the tools is 15.75 m/s

3 0
3 years ago
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