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Pie
3 years ago
7

Can someone please help

Mathematics
1 answer:
Artist 52 [7]3 years ago
4 0

Answer: dotted

Step-by-step explanation:

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(b+8)(b+2) please show work. I got b^2 + 10b + ?
kolezko [41]

Step 1. Apply FOIL method. bb+b*2+8b+8*2

Step 2. bb+2b+8b+8*2

Step 3. Add similar elements. bb+10b+8*2

Step 4. Apply exponent rule. b^2+10b+8*2

Step 5. Multiply the numbers.  b^2+10b+16

b^2+10b+16 is your answer.

6 0
3 years ago
The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. S
JulsSmile [24]

Answer:

32

Step-by-step explanation:

First, one theorem states that (arc AB - arc AX) / 2 = angle ACB. We know that arc AB is 176, so we have

(176 - arc AX) /2 = ∠ACB

Next, the Inscribed Angle Theorem states that

arc AX/2 = ∠ABX

multiply both sides by 2

56 * 2 = arc AX = 112

Therefore, ∠ACB = (176-112)/2 = 64/2 = 32

6 0
3 years ago
R – 1,823 = 2,312 if anyone knows what this is please let me know even though....nvm
zepelin [54]

Answer:

R = 4135

Step-by-step explanation:

Ain't a hundro % sure bro but I wish ya luck!

3 0
3 years ago
Read 2 more answers
How do I go about solving this. ​
notka56 [123]
<h2>Answer:</h2><h2>x=37.5° and angle ABC is 52.5°</h2><h2>Step-by-step explanation:</h2>

We know that angle CBD is a right angle.

We also know that angle ABE is 180°.

Our unknown angle values are angle DBE and angle CBA.

angle CBD minus angle ABE will be 90°.

angle ABC plus angle DBE must equal 90°.

Solving for x:

(x+15)+(x)=90°

(x+15-15)+(x)=90°-15

(x)+(x)=75°

2x=75°

2x/2=75°/2

x=37.5°

Checking the work:

ABC=37.5°+15=52.5°

CBD=90°

DBE=37.5°

In conclusion, ABC plus CBD plus DBE equals 180°

<em>Hope this helped!</em>

6 0
4 years ago
In ΔDEF, the measure of ∠F=90°, DE = 88 feet, and EF = 39 feet. Find the measure of ∠E to the nearest tenth of a degree.
Alex777 [14]
- 47 I think this is the answer
3 0
3 years ago
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