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kodGreya [7K]
3 years ago
14

Mary, who has type O blood, is expecting a child with her husband, who has type B blood. Mary's husband's father has type A bloo

d. What is the probability that the child will have type O blood
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

50% is the answer.

Step-by-step explanation:

All three persons have different blood groups.

Mary has O blood type.

Her husband has B blood type.

Her father in law has A blood type.

As everyone has different blood groups and the child's group depends on parents blood groups so we have 2 options left.

Hence, the probability that the child will have type O blood is = \frac{1}{2} =50%

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Answer:

<em>(12, 2)</em> is the original point on the graph of y=f(x).

Step-by-step explanation:

<u>Given:</u>

y= 5f(2(x+3))-4 has a point <em>(3, 6)</em> on its graph.

<u>To find:</u>

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<u>Solution:</u>

We are given that The point (3, 6) is on the graph of y= 5f(2(x+3))-4

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Let us the put the values and observe:

6= 5f(2(3+3))-4\\\Rightarrow 6= 5f(2(6))-4\\\Rightarrow 6= 5f(12)-4\\\Rightarrow 6+4=5f(12)\\\Rightarrow 5f(12)= 6+4\\\Rightarrow 5f(12)= 10\\\Rightarrow f(12)= \dfrac{10}{5}\\\Rightarrow f(12)= 2\\OR\\\Rightarrow 2=f(12)

Now, let us compare the above with the following:

y=f(x)

we get y = 2 and x = 12

So, the original point on graph of y=f(x) is <em>(12, 2).</em>

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Keywords: division, unit rate

Learn more about division at:

  • brainly.com/question/2048256
  • brainly.com/question/2115122

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