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3 years ago

Define force in your own words.

Physics

2 answers:

yaroslaw [1]3 years ago

5 0

Answer:

The push or pull on an object acted by another object

Elodia [21]3 years ago

3 0

Answer:

an influence that is able to change the motion of a body or create motion or stress in a stationary body. The magnitude of an influence is often calculated by multiplying the mass of the body by its acceleration.

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explain the fleming left-hand rule with the diagram and what will the direction of the induced current in the figure if the magn

iVinArrow [24]

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2 years ago

A car from the beginning was traveling at 27.8m/s when he stepped on the brakes and stopped. According to the DMV, this would le

Yuliya22 [10]

Answer:

-6.44 m/s²

Explanation:

Given:

Δx = 60 m

v₀ = 27.8 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (27.8 m/s)² + 2a (60 m)

a = -6.44 m/s²

3 0

3 years ago

A point charge of 6.0 nC is placed at the center of a hollow spherical conductor (inner radius = 1.0 cm, outer radius = 2.0 cm)

egoroff_w [7]

Explanation:

The given data is as follows.

q = 6.0 nC = $6 \times 10^{-9} C$

inner radius (r) = 1.0 cm = 0.01 m (as 1 cm = 100 m)

So, there will be same charge on the inner surface as the charge enclosed with an opposite sign.

Formula to calculate the charge density is as follows.

$\sigma = \frac{q_{in}}{A}$ .......... (1)

Since, area of the sphere is as follows.

A = $4 \pi r^{2}$ ........... (2)

Hence, substituting equation (2) in equation (1) as follows.

$\sigma = \frac{q_{in}}{4 \pi r^{2}}$

= $\frac{6 \times 10^{-9} C}{4 \times 3.14 \times (0.01)^{2}}$

= $0.477 \times 10^{-5}$

or, = 4.77 $\mu C/m^{2}$

Thus, we can conclude that the resulting charge density on the inner surface of the conducting sphere is 4.77 $\mu C/m^{2}$ .

5 0

3 years ago

How does a higher heat capacity affect the amount of time it takes for an object’s temperature to change?

Alenkasestr [34]

$higher~ specific ~heat ~capacity ~means ~ it ~has ~higher ~heat ~ energystorage$

8 0

3 years ago

During which two time intervals does the particle undergo equal displacement?

san4es73 [151]

Answer:

BC and DE

Explanation:

In the given figure, the velocity time graph is shown. We know that the area under v-t curve gives the displacement of the particle.

Area under AB, $d_1=\dfrac{1}{2}\times 2\times 10=10\ m$

Area under BC, $d_2=\dfrac{1}{2}\times 2\times 4=4\ m$

Area under CD, $d_3=\dfrac{1}{2}\times 2\times 7=7\ m$

Area under DE, $d_4=\dfrac{1}{2}\times 2\times 4=4\ m$

Area under EF, $d_5=\dfrac{1}{2}\times 2\times 3=3\ m$

So, form above calculations it is clear that, during BC and DE undergo equal displacement. Hence, the correct option is (c) "BC and DE = 4 meters".

4 0

3 years ago