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3 years ago

Explain why bond angle of H2O is greater than OF2

1 answer:

7 0

It's only a small difference (103 degrees versus 104 degrees in water), and I believe the usual rationalization is that since F is more electronegative than H, the electrons in the O-F bond spend more time away from the O (and close to the F) than the electrons in the O-H bond. That shifts the effective center of the repulsive force between the bonding pairs away from the O, and hence away from each other. So the repulsion between the bonding pairs is slightly less, while the repulsion between the lone pairs on the O is the same -- the result is the angle between the bonds is a little less.

Hope this helps!

You might be interested in

what is the order of decreasing bond length for a C-C bond composed of the following molecular orbitals?I. sp^3 - sp^3II. sp^2 -

skelet666 [1.2K]

Answer:

The decreasing order of bond length in the carbon - carbon bonds will be:

$C-C>C=C>C\equiv C$

Explanation:

Bond length is defined as average distance between two nuclei of bonded atoms in a molecule.Bond length is inversely proportional to the number of bonds present between two atoms.

$\text{Bond length} \propto \frac{1}{\text{Number of bonds}}$ ...[1]

Bond energy is defied as amount of energy required to break apart the bond of 1 mole of molecule into their individual atom. Bond energy is directly proportional to the number of bonds present between two atoms.

$\text{Bond Energy} \propto \text{Number of bonds}$ ..[2]

From [1] and [2]:

$\text{Bond length} \propto \frac{1}{\text{Bond energy}}$

$C-C: sp_3$ hybridized

$C=C: sp_2$ hybridized

$C\equiv C: sp$ hybridized

Extent of overlapping of orbitals in these hybridization;

$C\equiv C> C=C > C-C$

Higher the overlapping of orbital more closer will be both atoms to each other and shorter will be the bond lenght.

So, the decreasing order of bond length in the carbon - carbon bonds will be:

$C-C>C=C>C\equiv C$

8 0

2 years ago

at what temperature in celsius would a gas have volume of 13.5 L at a pressure of 0.723 atm, if it had a volume of 17.8 L at a p

Alex

Answer:

initial temperature= $-3.31^{\circ}C$

Explanation:

Assuming that the given follows the ideal gas nature;

$P_1=0.723atm$

$V_1=13.5L$

$T_1=?$

$P_2=0.612atm$

$V_2=17.8L$

$T_2=28 ^{\circ}C =273+28K=301K$

mole of gass will remain same at any emperature:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

putting all the value we get:

$T_2 =269.7K =-3.31 ^{\circ} C$

initial temperature= $-3.31^{\circ}C$

6 0

2 years ago

The density of thorium, which has the FCC structure, is 11.72 g/cm3. The atomic weight of thorium is 232 g/mol. Calculate (a) th

seropon [69]

Answer:

(a) a = 5.08x10⁻⁸ cm

(b) r = 179.6 pm

Explanation:

(a) The lattice parameter "a" can be calculated using the following equation:

$\rho = \frac{(N atoms/cell)*m}{V_{c}*N_{A}}$

where ρ: is the density of Th = 11.72 g/cm³, N° atoms/cell = 4, m: is the atomic weight of Th = 232 g/mol, Vc: is the unit cell volume = a³, and $N_{A}$ : is the Avogadro constant = 6.023x10²³ atoms/mol.

Hence the lattice parameter is:

$a^{3} = \frac{(N atoms/cell)*m}{\rho *N_{A}} = \frac{4 atoms*232 g/mol}{11.72 g/cm^{3} *6.023 \cdot 10^{23} atoms/mol} = 1.32 \cdot 10^{-22} cm^{3}$

$a = \sqrt[3]{1.32 \cdot 10^{-22} cm^{3}} = 5.08 \cdot 10^{-8} cm$

(b) We know that the lattice parameter of a FCC structure is:

$a = \frac{4r}{\sqrt{2}}$

where r: is the atomic radius of Th

Hence, the atomic radius of Th is:

$r = \frac{a*\sqrt{2}}{4} = \frac{5.08 \cdot 10^{-8} cm*\sqrt{2}}{4} = 1.796 \cdot 10^{-8} cm = 179.6 pm$

I hope it helps you!

4 0

3 years ago

Read 2 more answers

Name all nonmetals that’s are halogens PLEASE HELP ASAP

Nikitich [7]

Answer:

chlorine, fluorine, bromine, iodine, Xenon, and radon

7 0

3 years ago

A person's heartbeat is 91 beats per minute. If his/her heart beats 3.1e9 times in a lifetime, how long (in whole years) does th

Nat2105 [25]

During a lifetime, a heart beats 3.1 x 10^9 times and it beats 91 times in one minute.
Thus, we can use cross multiplication to determine the number of minutes in the person's lifetime as follows:
number of minutes in person's lifetime = (3.1 x 10^9) / 91 = 34.0659 x 10^6 min

One year has 365.25 days (disregarding leap). Each day has 24 hours and each hour has 60 minutes.
Therefore,
one year = 365.25 x 24 x 60 = 525960 minutes

We can now use cross multiplication to determine the number of years of a person's lifetime as follows:
number of years = (34.0659 x 10^6 x 1) / 525960 = 64.76899 years.

3 0

3 years ago