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swat32
3 years ago
7

Explain why bond angle of H2O is greater than OF2

Chemistry
1 answer:
atroni [7]3 years ago
7 0
It's only a small difference (103 degrees versus 104 degrees in water), and I believe the usual rationalization is that since F is more electronegative than H, the electrons in the O-F bond spend more time away from the O (and close to the F) than the electrons in the O-H bond. That shifts the effective center of the repulsive force between the bonding pairs away from the O, and hence away from each other. So the repulsion between the bonding pairs is slightly less, while the repulsion between the lone pairs on the O is the same -- the result is the angle between the bonds is a little less.

Hope this helps!
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If 3.0g of H20 actually forms what is the percentage yield
Sati [7]
Percent yield is expressed as the ratio of the actual yield and the theoretical yield of the reaction multiplied by 100 to get the percent value. The actual yield is usually given in a problem. The theoretical yield is calculated from the reaction. For this problem, it cannot be solved since we cannot obtain the theoretical yield.
5 0
3 years ago
Butane is used as a fuel in disposable lighters. Write the Lewis structure for each isomer of butane.
AVprozaik [17]

Answer:

Lewis structure for isomers of butane has been given below.

Explanation:

Butane is a saturated alkane with molecular formula C_{4}H_{10}. Due to different positing of methyl groups, positional isomerism exists in butane.

Butane has two positional isomers with same molecular formula. One is n-butane and another one is isobutane. Lewis structures of these two isomers have been given below.

3 0
3 years ago
Suppose you have 250g of gold(I) Chloride. How many grams of Gold do you have?
solniwko [45]

29.26 gram

Explanation:

No of molecules = no of mole × Avogadro's number

No of molecules = mass in gram/ molar mass × Avogadros number

Mass in gram =No of molecules×molar mass / Avogadros number

Mass in gram = 3.012 ×10^23 × 58.5/6.02×10^23

29.26 gram

4 0
2 years ago
Find the precent composititions in (NH4)2S
ruslelena [56]
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8 0
3 years ago
Standard Reduction Potentials in Aqueous Solution at 25 °C
7nadin3 [17]

Answer:

Hope this helps:)

Explanation:

The values for the table entries are reduction potentials, so lithium at the top of the list has the most negative number, indicating that it is the strongest reducing agent. The strongest oxidizing agent is fluorine with the largest positive number for standard electrode potential.

Elemental fluorine, for example, is the strongest common oxidizing agent.

Lithium metal is therefore the strongest reductant (most easily oxidized) of the alkali metals in aqueous solution. The standard reduction potentials can be interpreted as a ranking of substances according to their oxidizing and reducing power

6 0
3 years ago
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