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velikii [3]
3 years ago
10

You have 263 mL of liquid mercury, what is the mass of mercury that you have?

Chemistry
1 answer:
Gelneren [198K]3 years ago
7 0

Answer:3,550.5 g

Explanation:

Mass= density×volume

Mass= 13.5g/m.l×263ml

Mass=3,550.5 g

Please add me the brainleist!!!!!!!!

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The enthalpy change for the explosion of ammonium nitrate with fuel oil is –7198 kJ for every 3 moles of NH4NO3. What is the ent
anastassius [24]

Answer:

−2399.33 kJ

Explanation:

If NH₄NO₃ reacts with fuel oil to give a ΔH of -7198 for every 3 moles of NH₄NO₃

What is the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction

∴ For every 1 mole, we will have \frac{1}{3} of the total enthaply of the 3 moles

so, to determine the 1 mole; we have:

\frac{1}{3}*(-7198kJ)

= −2399.33 kJ

∴ the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction = −2399.33 kJ

7 0
3 years ago
I NEED HELP PLEASE!!!!!
lisov135 [29]
Atoms can be divided more so thats not true. atoms from the same element arent all nesacarly identical because of isotopes
7 0
3 years ago
Read 2 more answers
Aspirin (C9H8O4) is an acid which can be titrated with a base to determine purity. If an aspirin tablet weighing 0.615 g is titr
Iteru [2.4K]

Answer:

67.4 % of C₉H₈O₄

Explanation:

To make titrations problems we know, that in the endpoint:

mmoles of acid = mmoles of base

mmoles = M . volume so:

mmoles of acid = 20.52 mL . 0.1121 M

mmoles of acid = mg of acid / PM (mg /mmoles)

Let's determine the PM of aspirin:

12.017 g/m . 9 + 1.00078 g/m . 8 + 15.9994 g/m . 4 = 180.1568 mg/mmol

mass (mg) = (20.52 mL . 0.1121 M) . 180.1568 mg/mmol

mass (mg) = 414.4 mg

We convert the mass to g → 414.4 mg . 1g / 1000mg = 0.4144 g

We determine the % → (0.4144 g / 0.615 g) . 100 = 67.4 %

6 0
3 years ago
Find the average speed of a person who swims 105 m in 70 s
spin [16.1K]

Answer:

v = 1.5 m/s

Explanation:

Given that,

Distance covered by a person, d = 105 m

Time taken, t = 70 s

We need to find the average speed of the person. We know that the average speed is given by :

v=\dfrac{d}{t}\\\\v=\dfrac{105\ m}{70\ s}\\\\v=1.5\ m/s

So, the average speed of the person is equal to 1.5 m/s.

4 0
3 years ago
Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these are decomposed, the sulfur dioxide produce
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To determine the mass of oxygen per gram of sulfur for sulfur dioxide, we simply obtain the ratio of the mass of oxygen and the mass of sulfur produced from the decomposition of sulfur dioxide. All other values given in the problem statement above are just to confuse us that the question is a difficult one. We do as follows:

mass of oxygen per gram sulfur = 3.45 g / 3.46 g
mass of oxygen per gram sulfur = 0.9971 g O2 / g S
4 0
3 years ago
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