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Tema [17]
3 years ago
8

Which of the following is an example of a metallic bond? A. Chlorine accepts 1 electron from calcium to form a stable bond. B. S

odium gives 1 electron to chlorine to form a stable bond. C. Silver ions are surrounded by a large group of valence electrons.
Chemistry
1 answer:
Law Incorporation [45]3 years ago
7 0
Metallic bonds exist between the atoms of metal elements and their electrons, therefore, the answer is C.
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Consider the molecules: scl2, f2, cs2, cf4, and brcl. select the choice where the bonds of the molecules are arranged in order o
elena-s [515]

The polarity of a bond depends on the difference in electronegativities of the atoms involved in bonding. Greater this difference, greater is the polarity

1) In SCl2 we have the S-Cl bond

Electronegativity values: S = 2.5, Cl = 3

Difference = 3.0 -2.5 = 0.5

2) In F2 we have the F-F bond

Electronegativity value: F = 4.0

Difference = 4.0-4.0 = 0

3) In CS2 we have the C-S bond

Electronegativity value: C = 2.5, S = 2.5

Difference = 2.5 -2.5 = 0

4) In CF4 we have the C-F bond

Electronegativity values: C = 2.5, F = 4.0

Difference = 4.0 -2.5 = 1.5

5) In BrCl we have the Br-Cl bond

Electronegativity values: Br = 2.8, Cl = 3

Difference = 3.0 -2.8 = 0.2

Therefore, the increasing order of polarity is

F2 = CS2 < BrCl < SCl2 < CF4

5 0
3 years ago
The pH of a basic solution is 9.77. What is [OH⁻]?
uysha [10]

The  [OH⁻] of the solution is 5.37×10⁵ M.

<h3 /><h3>What is pOH?</h3>

This is the negative logarithm to base 10 of hydroxy ion [OH⁻] concentration.

To calculate the hydroxy ion [OH⁻] concentration we use the formula below.

Note:

  • pH+pOH = 14
  • pOH = 14-pH
  • pOH = 14-9.77
  • pOH = 4.27

Formula:

  • [OH⁻] = 1/10^{pOH}................. Equation 1

Given:

  • pOH = 4.27

Substitute the value into equation 1

  • [OH⁻] = 1/10^{4.27}
  • [OH⁻]  = 5.37×10⁵

Hence, The [OH⁻] of the solution is 5.37×10⁵ M.

Learn more about hydroxy ion concentration here: brainly.com/question/17090407

7 0
2 years ago
Read 2 more answers
Question 11. Identify the reducing agent <br> Sn+2 + AG 0 —&gt; Sn0 + Ag+
Temka [501]

Answer:

Ag 0 is the reducing agent.

Explanation:

Reducing -> gaining electrons

Oxidizing -> losing electrons

Ag lost electrons (became more positive) since it went from a 0 charge to a +1 charge. Therefore it was oxidized. Ag+ is the oxidized product. Reactants that create an oxidized product are called reducing agents. This would make Ag 0 the reducing agent in this reaction.

4 0
2 years ago
32. Barium sulfate, BaSO4, is a white crystalline solid that is insoluble in water. It is used by doctors to diagnose
DIA [1.3K]

Answer:

42

Explanation:

bygyytrdesf

7 0
2 years ago
a sample of gas measures 5 liters at 1 atm. to change the volume to a 3.5 liters at constant temperature what pressure must be a
Scorpion4ik [409]

Answer:

0.7atm

Explanation:

3.5/5 because constant temperature

8 0
3 years ago
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