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matrenka [14]
3 years ago
6

What is the electron configuration of an element with an atomic number of 10?

Chemistry
1 answer:
hram777 [196]3 years ago
3 0

Explanation:

From the periodic table the element with atomic number 10 is neon and this element is a noble gas.

It's electron configuration is

<h2>1 {s}^{2} \:   \:  \:  \:  \: 2 {s}^{2}  \:  \:  \:  \:  \: 2 {p}^{6}</h2>

Hope this helps you

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A particular reaction, A- products, has a rate that slows down as the reaction proceeds. The half-life of the reaction is found
Thepotemich [5.8K]

Explanation:

Half life of zero order and second order depends on the initial concentration. But as the given reaction slows down as the reaction proceeds, therefore, it must be second order reaction. This is because rate of reaction does not depend upon the initial concentration of the reactant.

a. As it is a second order reaction, therefore, doubling reactant concentration, will increase the rate of reaction 4 times. Therefore, the statement  a is wrong.

b. Expression for second order reaction is as follows:

\frac{1}{[A]} =\frac{1}{[A]_0} +kt

the above equation can be written in the form of Y = mx + C

so, the plot between 1/[A] and t is linear. So the statement b is true.

c.

Expression for half life is as follows:

t_{1/2}=\frac{1}{k[A]_0}

As half-life is inversely proportional to initial concentration, therefore, increase in concentration will decrease the half life. Therefore statement c is wrong.

d.

Plot between A and t is exponential, therefore there is no constant slope. Therefore, the statement d is wrong

8 0
3 years ago
He wants to increase the energy of emitted electrons . Based on the research of Albert Einstein, what is the best way for him to
pishuonlain [190]

To increase the energy of the emitted electrons, the frequency of the incident light on the metal must be increased.

<h3>What is energy of emitted electron?</h3>

The maximum energy of an emitted electron is equal to the energy of a photon for frequency f (E = hf ), minus the energy required to eject an electron from the metal's surface, also known as work function.

Ee = E - W

<h3>Energy of the emitted electron</h3>

The energy of emitted electrons based on the research of Albert Einstein is given as;

E = hf

where;

  • h is planck's constant
  • f is frequency of incident light on the metal

Thus, to increase the energy of the emitted electrons, the frequency of the incident light on the metal must be increased.

Learn more about energy of electron here: brainly.com/question/11316046

#SPJ1

8 0
2 years ago
How many grams of h20 are produced if 75g of CO2 are produced. (Work Shown with the answer would be preferred.)
Agata [3.3K]
2:7 ratio of ethane to O2 = 15:x 9solve for x)
x=52.5 mol O2
5 0
3 years ago
Which do you think has more mass, 1 mole of fructose, 1 mole of sucrose or 1 mole of aspartame? Explain your reasoning.
pogonyaev

Answer:

i think they would be all the same

Explanation:

they sound like sugars

6 0
3 years ago
Read 2 more answers
I don't know how to do this can I get the answers plz it's due in 1 hour
katrin [286]
Okay, so even if I just gave you the answers, your teacher needs work on it too so it'll be easier/better if I just explain how to do it.
Basically, both sides need to have the same number of molecules. To do this, we make charts. This is the first side of number one:
Na - 1
Mg- 1
F - 2
The subscript gives F two molecules, and the other ones only each have one. This is the second side:
Na- 1
Mg- 1
F- 1
So they're not equal. To fix this, we add coefficients. These are numbers that are going to appear in the front of each compound/element and changes the number of molecules of the WHOLE compound/element. We need two F on the second side, so we'll put a coefficient of 2 in front of NaF. The new chart for the second side is this:
Na- 2
Mg- 1
F- 2
Now we've fixed the F, but now Na is off! So let's go to the first side again and see what we can do. We can put a 2 in front of the Na. The new chart is this:
Na- 2
Mg -1
F- 2
Now both sides are the same. The full new equation is:
2Na + MgF(sub2) = 2NaF + Mg
Basically, do this for all of them. Feel free to ask more questions.
4 0
3 years ago
Read 2 more answers
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