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viktelen [127]
3 years ago
7

The substance gray tin is found to crystallize in a cubic lattice, with an edge length of 646.0 pm. if the density of solid gray

tin is 5.850 g/cm3, how many sn atoms are there per unit cell?
Chemistry
1 answer:
saveliy_v [14]3 years ago
8 0

First find the volume of the cubic lattice given edge length of 646 pm or 6.46x10^-8 cm.

volume = (6.46x10^-8 cm)^3

volume = 2.7x10^-22 cm^3

 

The total mass of the lattice is:

mass = (5.850 g/cm^3) * 2.7x10^-22 cm^3

mass = 1.577x10^-21 grams

 

The molar mass of tin is 118.71 g/mol and the Avogadros number is 6.022 x 10^23 atoms/mol, hence:

 

Sn atoms = [1.577x10^-21 g / (118.71 g/mol)] * 6.022 x 10^23 atoms/mol

Sn atoms = 8 atoms

You might be interested in
rank the four gases (air, exhaled air, gas produced from the decomposition of H2O2, gas from decomposition of NaHCO3, in order o
SVEN [57.7K]

Answer: H₂O₂ (94%) > Air (23%) > Exhaled air (13%) > NaHCO₃ (0%)


Initial important note:


Although NaHCO₃ contents oxygen atoms, and you can calculate its compositoin, the resulting gas does not containg pure oxygen gas (O₂). For the comparisson it is not useful to calculate the content of oxygent atoms, but the concentration of O₂ gas. As such, the gas from NaHCO₃ contains 0% of pure O₂, that is why it is ranked last.


1) Air:


Source: internet


Approximate 23%. It is variable, because air is not a pure substance but a mixture of gases, whose compositon is not unique.


2) Exhaled air:


Source: internet.


Approximate 13%. The compositon of the air changes in our lungs, due to the respiration process: we inhale fresh air with around 23% of oxygen, part of this oxygen pass to the cells (lungs - blood - heart - cells) and then it is exhaled with a lower content of air and a greater content of CO₂


3) Air from the decomposition of H₂O₂.


In this case we can do a chemical calculation, since we can state the chemical equation of the reaction:


i) Chemical Equation:


H₂O₂ (g) → H₂ (g) + O₂ (g)


ii) mole ratio of the products 1 mol H₂ : 1 mol O₂


iii) convert moles into mass (grams)


1 mol H₂ × 2 × 1.008 g/mol = 2.016 g


1 mol O₂ × 2 × 15.999 g/mol = 31.998 g


Composition, % = [31.998 g / (2.016 g + 31.998 g) ] × 100 ≈ 94%



4) Air from the decomposition of NaHCO₃:


i) chemical equation:


2 NaHCO₃(s) → Na₂CO₃(s) + CO₂(g) + H₂O(g)


ii) mole ratio: take into account only the gases in the products:


1 mol CO₂ (g) : 1 mol H₂O


iii) mass in grams


CO₂: molar mass ia approximately 44.01 g/mol


H₂O: molar mass is approximately 18.02 g/mol


iii) Those gases although have oxygen atoms, do not hae free oxygen gas, which is what we are compariing. That means, that from the decomposition of NaHCO₃ you get 0% oxygen gas.


5) The result is:


H₂O₂ (94%) > Air (23%) > Exhaled air (13%) > NaHCO₃ (0%)

7 0
3 years ago
Read 2 more answers
At 25 °C, only 0.0990 mol of the generic salt AB3 is soluble in 1.00 L of water. What is the Ksp of the salt at 25 °C? AB3(s)↽−−
maksim [4K]

Answer:

Ksp=2.59x10^{-3}

Explanation:

Hello,

In this case, given the 0.0990 moles of the salt are soluble in 1.00 L of water only, we can infer that the molar solubility is 0.099 M. Next, since the dissociation of the salt is:

AB_3\rightleftharpoons A^{3+}+3B^-

The concentrations of the A and B ions in the solution are:

[A]=0.099 \frac{molAB_3}{L}*\frac{1molA}{1molAB_3}  =0.0099M

[B]=0.099 \frac{molAB_3}{L}*\frac{3molB}{1molAB_3}  =0.000.297M

Then, as the solubility product is defined as:

Ksp=[A][B]^3

Due to the given dissociation, it turns out:

Ksp=[0.099M][0.297M]^3\\\\Ksp=2.59x10^{-3}

Regards.

4 0
4 years ago
When 0.215 mol of a gas is placed into a 34.25 mL container at 125.0°C, 1
horrorfan [7]

Answer:

205.12 atm

Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

R = 0.0821 Latm/perK)

T = temperature (K)

n = number of moles (mol)

According to the information in this question;

P = ?

V = 34.25 mL = 34.25 ÷ 1000 = 0.03425L

n = 0.215 mol

T = 125.0°C = 125 + 273 = 398K

Using PV = nRT

P = nRT ÷ V

P = (0.215 × 0.0821 × 398) ÷ (0.03425)

P = 7.025 ÷ 0.03425

P = 205.12 atm

8 0
3 years ago
9. A student is dissolving sugar in water. What can
pychu [463]

Answer:

D

Explanation:

Sugar will dissolve faster when you stir the solution quickly because the act of stirring increases kinetic energy which increases the temperature.

4 0
3 years ago
Read 2 more answers
Suppose that H2SO4 was used in the reaction instead of HCl. How many moles of NaOH would neutralize 1 mole of H2SO4?
arlik [135]

Answer: Hence, 2 moles of NaOH would neutralize 1 mole of H_2SO_4

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

One mole of hydrochloric acid neutralizes one mole of sodium hydroxide to give one mole of sodium chloride and one mole of water

When sulfuric acid is used in the place of HCl , 1 mole of sulfuric acid will neutralizes the 2 mole of sodium hydroxide and gives one mole of sodium sulfate and 2 moles of water. As we can see from the reaction:

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

Hence, 2 moles of NaOH would neutralize 1 mole of H_2SO_4

5 0
3 years ago
Read 2 more answers
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