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Marizza181 [45]
3 years ago
10

Using a horizontal force of 200N,we intend to move a wooden cabinet across a floor at constant velocity.What is the friction for

ce that will be exerted on the cabinet?
With explanation please
Physics
1 answer:
IgorLugansk [536]3 years ago
8 0

Answer:

-200 N

Explanation:

The cabinet moves at constant velocity, so that means there's no acceleration.

Applying Newton's second law to the cabinet:

∑F = ma

F + 200 = 0

F = -200

The friction force is 200 N in the opposite direction.

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4 0
2 years ago
Consider blood (density 1025 kg/m3) flowing through an artery with circular cross section that looks like this: Ignore viscosity
Klio2033 [76]

The given question is incomplete. The complete question is attached with an image below.

Explanation:

Mass flow rate through region A will be calculated as follows.

Rate = \rho \times A \times \mu

       = \rho \times \pi \times R^{2} \times \mu

       = 1025 \times 3.14 \times (0.5 \times 10^{-2})^{2} \times 30 \times 10^{-2}

       = 24138.75 \times 10^{6} kg/s

Therefore, we can conclude that the mass flow rate through region A is 24138.75 \times 10^{6} kg/s.

8 0
3 years ago
A large boulder falls from a cliff located 1,044 meters away from a herd of elephants. The temperature of the air is 29°C. How l
Lynna [10]
The answer you would be letter D 343 m/s 

3 0
3 years ago
A 6-in-wide polyamide F-1 flat belt is used to connect a 2-in-diameter pulley to drive a larger pulley with an angular velocity
Likurg_2 [28]

Answer:

a) Fc = 4.15 N, Fi = 435.65 N, (F1)a = 640 N, and F2  = 239.6 N,

b) Ha = 1863.75 N, nfs = 1 , length = 11.8 mm

Explanation:

Given that:

γ= 9.5 kN/m³ = 9500N/m3

b = 6 inches = 0.1524 m

t = 0.0013 mm

d = 2 inches  = 0.0508 m

n = 1750 rpm

H_{nom}=2hp=1491.4W

L = 9 ft = 2.7432 m

Ks = 1.25

g = 9.81 m/s²

a)

w=\gamma b t = 9500* 0.1524*0.0013=1.88N/m

V=\frac{\pi d n}{60} =\pi *0.0508*1750/60=4.65 m/s

F_c=\frac{wV^2}{g}=1.88*4.65^2/9.81=4.15N

(F_1)_a=bF_aC_pC_v=0.1524*6000*0.7*1=640N

T=\frac{H_{nom}n_dK_s}{2\pi n}= \frac{1491*1.25*1}{2*\pi*1750/60}=10.17Nm

F_2=(F_1)_a-\frac{2T}{D}= 640-\frac{2*10.17}{0.0508} =239.6N

F_i=\frac{(F_1)_a+F_2}{2} -F_c=435.65N

b)

H_a=1491*1.25=1863.75W

n_f_s=\frac{H_a}{H_{nom}K_S }=1

dip = \frac{L^2w}{8F_i} =\frac{2.7432*1.88}{435.65}=11.8mm

7 0
3 years ago
Technician A says that a waste spark ignition system fires two spark plugs at the same time. Technician B says that the waste sp
Alina [70]

Answer:

d. neither technicians a and b

6 0
3 years ago
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