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Marizza181 [45]
3 years ago
10

Using a horizontal force of 200N,we intend to move a wooden cabinet across a floor at constant velocity.What is the friction for

ce that will be exerted on the cabinet?
With explanation please
Physics
1 answer:
IgorLugansk [536]3 years ago
8 0

Answer:

-200 N

Explanation:

The cabinet moves at constant velocity, so that means there's no acceleration.

Applying Newton's second law to the cabinet:

∑F = ma

F + 200 = 0

F = -200

The friction force is 200 N in the opposite direction.

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Find the position vector of a particle that has the given acceleration and the specified initial velocity and position. a(t) = 1
kondor19780726 [428]

Answer:

Explanation:

Given

Acceleration a(t)=14t\hat{i]+\sin (t)\hat{j}+\cos (2t)\hat{k}[/tex]

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we know a=\frac{\mathrm{d} v}{\mathrm{d} t}

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and \frac{\mathrm{d} r}{\mathrm{d} t}=v(t)

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at t=0

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4 0
3 years ago
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Answer:

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Explanation:

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100km/hr=100*5/18 m/sec=27.77m/sec

the distance travelled before it stops (s)=50m

let the acceleration of the car be a

The final velocity of the car is 0.

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a=7.712m/sec^{2}

We know that F=Ma

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