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Nadya [2.5K]
3 years ago
10

Two identical resistors are connected first in series and second in parallel. The equivalent resistances of the two types of con

nections are, respectively, RS and RP. What is the ratio RS/RP?
Physics
1 answer:
trasher [3.6K]3 years ago
4 0

Answer:

\frac{R_{s} }{R_{p} } =\frac{R_{1} }{R_{2} }+\frac{R_{2} }{R_{1} } +2

Explanation:

We have series and parallel combination of two resisters R_{1} and R_{2}.

Series combination is

R_{s}= R_{1}+R_{2} and Parallel is R_{p} = (\frac{1}{R_{1}}+\frac{1}{R_{2}}  )^-1

Now dividing series equivalent resistance by parallel resistance gives us

\frac{R_{s} }{R_{p} } =\frac{R_{1} }{R_{2} }+\frac{R_{2} }{R_{1} } +2.

Note! series Combination is simply superposition of two elements (resisters in this case ) in a circuit.

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7.2 kilowatts

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H = 532 m

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d = 1020 m

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A ball is suspended by a lightweight string, as shown in the figure above.
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<u>Answer </u>

A. 1 and 2

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P.E = height × gravity × mass. The height referred here is the perpendicular height. Gravity and mass are constant in this case.

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