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3 years ago

What are the two varieties of friction?

Physics

1 answer:

murzikaleks [220]3 years ago

6 0

There are two main types of friction, static friction and kinetic friction. Static friction operates between

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A large truck breaks down out on the road and receives a push back to town by a small compact car.

Anton [14]

Answer:

A True. It agrees with Newton's third law

3 True. The car pushes the truck and goes at constant speed

Explanation:

To examine the final answers, we must silver the solution of the problem, if we see Newton's third law, action and reaction, we see that the car pushes the truck the action, the truck must oppose this force with a force applied on the car of equal magnitude, but opposite direction

In view of the above, let's review the statements.

A True. It agrees with Newton's third law

B False. Violate Newton's third law

C False violate Newton´s third law

D False. The force is exerted by the car not specifically by the engine

E Faults if no force is exerted the truck should stop due to friction

Second question

If the two vehicles move at the same speed, the resulting force on each of them must be zero

1 False. If the truck doesn't get nine, it can't go at cruising speed

2 False if the car is accelerating it cannot go at constant speed

3 True. The car pushes the truck and goes at constant speed

4 False. If the truck slows it should slow down

5 0

3 years ago

How to change V=72km/hr to m/s

lapo4ka [179]

Multiply by (1000 meters / 1 km).
Then multiply by (1 hour / 3600 seconds).

Both of those fractions are equal to ' 1 ', because the top
and bottom numbers are equal, so the multiplications
won't change the VALUE of the 72 km/hr. They'll only
change the units.

(72 km/hour) · (1000 meters / 1 km) · (1 hour / 3600 seconds)

= (72 · 1000 / 3600) (km·meter·hour / hour·km·second)

= 20 meter/second

7 0

4 years ago

Calculate the mass of a lorry that has a momentum of 4600 kg m/s and a velocity of 15m/s. Give your answer to two decimal places

KiRa [710]

Mass = momentum / velocity = 4600 / 15 = ..... Kg

6 0

3 years ago

Two people are pulling a boat through the water. Each exerts a force of 600 N directed at a 30.0 angle relative to the forward m

VashaNatasha [74]

It sounds as though the two people are standing in front of the boat on opposite sides of it, so that they both make an angle of 30.0° with the axis of the boat, as in the attached free body diagram (ignoring the force of buoyancy and the weight of the boat).

By Newton's second law, the net vertical force is

∑ F = P₁ sin(60.0°) + P₂ sin(120.0°) - R = 0

where upward is positive and downward is negative, and the right side is 0 because the boat moves with constant velocity and thus zero acceleration.

We're told that P₁ = P₂ = 600 N, and we know sin(60°) = sin(120°), so the above reduces to

R = 2 P sin(60.0°) = 2 (600 N) sin(60.0°) ≈ 1040 N

7 0

3 years ago

URGENT QUICK PLEASE ANSWER WITH FULL DETAILS HOW TO SOLVE!!!!! WILL GIVE BRAINLIEST!!!!!!

e-lub [12.9K]

Answer:

I hope this helps.

Explanation:

Vs/Vp = Ns/Np

Vs/9 = 30/300

Vs/9 = 1/10

Vs= 9/10 = 0.9 volts

It is a Step down transformer. This is because the number of turns on the primary coil is greater than that on the secondary coil.

7 0

3 years ago