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Alex787 [66]
2 years ago
13

current is passed through two parallel conductors in the same direction. If the conductors are placed near each other,they will​

Physics
1 answer:
svlad2 [7]2 years ago
6 0

If current is passed through two parallel conductors in the same direction and the conductors are placed near each other, they will​ attract each other.

<h3>What is electric current?</h3>

Electric current can be defined as the flow of electrons.

Since electrons are easily removed from atom and are very mobile, the flow of electrons constitute an electric current.

Materials which allow electric current to flow through them are known as conductors. Examples of conductors are metals, and electrolytes.

On the other hand, materials which do not allow electric current to pass through them are known as insulators. Examples of insulators are wood and rubber.

The flow of current is known as electricity.

Parallel conductors with current flowing through them in the same direction are attracted to each other as a result of a magnetic field produced by the flow of current.

In conclusion, conductors allow electric current to pass through and the flow of current through a conductor produces a magnetic field.

Learn more about parallel conductors at: brainly.com/question/17148082

#SPJ1

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A block of wood measuring 2.75 cm x 4.80 cm x 7.50 cm has a mass of 84.0 g. will the block of wood sink or float in water?
KIM [24]
The volume of the block of wood is given by length × width ×height
 = 2.75 × 4.80 × 7.5
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Density is given by mass/volume
Thus = 84.0 g/ 99 cm³
         = 0.848 g/cm³
Hence;  since the block is less dense than water (1 g/cm³) it will float
6 0
3 years ago
A pump increases the pressure in the flow of water from 120 kPa to 400 kPa. The inlet and outlet diameters are 9 cm and 3 cm res
Alina [70]

Answer:

4.433 kW

Explanation:

Suppose the flow rate is the same at the inlet and outlet at 57 m3/hr.

Since 1 hour = 60 minutes = 3600 seconds we can calculate the flowrate in m3/s

\dot{V} = 57 / 3600 = 0.0158 m^3/s

As we are neglecting loss from friction and elevations changed, the power delivered by the pump is the product of the change in pressure and the flow rate

P = \Delta P \dot{V} = (400 - 120)*0.0158 = 4.433 kW

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If the distance between a neutral atom and a point charge is quadrupled, by what factor does the force on the atom by the point
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A ball is Thrown Upward with An initial velocity of 30 m/s , How high does it rise from the ground when the ball reaches the hig
kobusy [5.1K]

Answer:

  • The maximum height reached by the ball is 45.92 m
  • Time taken to fall down to half of its height is 2.2 s

Explanation:

Given;

initial velocity of the ball, u = 30 m/s

final velocity of the ball at the highest point, v = 0

The maximum height reached by the ball is calculated as;

v² = u² - 2gh

where;

h is the maximum height reached by the ball

0 = 30² - (2 x 9.8)h

19.6h = 900

h = 900 / 19.6

h = 45.92 m

Time taken to fall to half of its height is calculated as;

when falling down, the final velocity v becomes the initial velocity = 0.

Apply the following kinematic equation;

h = ut + ¹/₂gt²

h = 0 + ¹/₂gt²

h = ¹/₂gt²

where;

h = 45.92 m is the maximum height reached

half of h = 45.92 / 2 = 22.96 m

22.96 = ¹/₂gt²

t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 22.96}{9.8} }\\\\t = 2.2 \ s

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