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3 years ago

A car starts from rest down a straight, flat road and gets up to 22 m/s after 33 seconds.

Physics

1 answer:

den301095 [7]3 years ago

5 0

Answer:

Explanation:

Acceleration = distance / time

= 22 / 33 = 2/3

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viewed from earth two stars form an angle of 76.04 degrees. StarA is 23.30 light years from earth star Bis 34.76 light years fro

Mama L [17]

The observation point on Earth and the two stars form a triangle. The two sides of the triangle are 23.3 ly and 34.76 ly and their included angle is 76.04°. We can use the cos rule to find the third side, which is the distance between the two stars.
c² = a² + b² - 2abCos(C)
c² = (23.3)² + (34.76)² - 2(23.3)(34.76)Cos(76.04)
c = 36.88 light years.

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4 years ago

What shoreline feature would develop if the global sea level were to rise considerably

valentinak56 [21]

Wat does that mean I don't understand this

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3 years ago

A boy and his skateboard have a combined mass of 65KG what is the speed of the boy and skateboard if they have a momentum of 275

Pavel [41]

Answer:

v=4.231m/s

Explanation:

p=mv

275=(65)v

275/65=v

v=4.231

7 0

4 years ago

The gravitational force between two objects is 45,000 N. What will be the gravitational force between the two objects if the dis

sweet [91]

The gravitational force would be 180,000 N if the distance is reduced by one- half.

According to Newton's law of gravitation, the force of attraction between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them.

Therefore, the force F between the two masses when they are at a distance d apart can be written as

$F \alpha\frac{1}{d^2}$ ........(1)

When the distance between the two objects is reduced to one- half, then the new force F₁ is given by,

$F_1\alpha\frac{1}{(\frac{d}{2})^2} \\ F_1\alpha\frac{4}{d^2} ......(2)$

Divide equation (2) by equation (1)

$\frac{F_1}{F} =4\\ F_1 =4F$

Substitute 45,000 N for F.

$F_1 =(4)(45,000 N)\\ = 180,000 N$

If the distance between the two objects is reduced by one- half, the force between them has a value 180,000 N.

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3 years ago

the crankshaft of an engine increases its spin from 1,000 to 2,000 rpm in 0.50 s what is its angular acceleration

PilotLPTM [1.2K]

Answer:

angular acceleration = 209.44 [rad/s^2]

Explanation:

First we have to convert the velocities which are in revolutions per minute to radians on second.

where:

$w_{0} = 1000 [\frac{rev}{min}]*[\frac{2\pi rad }{1rev}] * \frac{1min}{60s} = 104.7[\frac{rad}{s} ]\\w = 2000 [\frac{rev}{min}]*[\frac{2\pi rad }{1rev}] * \frac{1min}{60s} = 209.4[\frac{rad}{s} ]$

Now we can find the angular acceleration:

$w=w_{0} + \alpha *t\\\alpha =\frac{w-w_{0} }{t} \\\alpha =\frac{209.43-104.71}{\0.5 } \\\alpha = 209.44[\frac{rad}{s^{2} } ]$

3 0

4 years ago