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3 years ago

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In lenzs law: If the current flow along the direction of deflection of the galvanometer, predict the direction of current in the

face of the coil closer to the bar magnet in steps 2 and 3.
Q2.If clockwise direction of current indicate south pole and counter clockwise indicates north of a magnet, predict the polarity of the face of the coil closer to the bar magnet in steps 2 and 3. what can u conclude from here

1 answer:

sertanlavr [38]3 years ago

7 0

Answer:

this answer is only for points

Explanation:

Mark me as a brain list please

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To introduce you to the concept of escape velocity for a rocket. the escape velocity is defined to be the minimum speed with whi

Mama L [17]

A projectile fired upward from the Earth's surface will usually slow down, come momentarily to rest, and return to Earth. For a certain initial speed, however it will move upward forever, with its speed gradually decreasing to zero just as its distance from Earth approaches infinity. The initial speed for this case is called escape velocity. You can find the escape velocity v for the Earth or any other planet from which a projectile might be launched using conservation of energy. The projectile of mass m leaves the surface of the body of mass M and radius R with a kinetic energy Ki = mv²/2 and potential energy Ui = -GMm/R. When the projectile reaches infinity, it has zero potential energy and zero kinetic energy since we are seeking the minimum speed for escape. Thus Uf = 0 and Kf = 0. And from conservation of energy,
Ki + Ui = Kf + Uf
mv²/2 -GMm/R = 0
∴ v = √(2GM/R)

This is the expression for escape velocity.

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3 years ago

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An air balloon is moving upward at a constant speed of 3 m/s. Suddenly a passenger realizes that she left her camera on the grou

frosja888 [35]

Answer:t=0.3253 s

Explanation:

Given

speed of balloon is $u=3\ m/s$

speed of camera $u_1=20\ m/s$

Initial separation between camera and balloon is $d_o=5\ m$

Suppose after t sec of throw camera reach balloon then,

distance travel by balloon is

$s=ut$

$s=3\times t$

and distance travel by camera to reach balloon is

$s_1=ut+\frac{1}{2}at^2$

$s_1=20\times t-\frac{1}{2}gt^2$

Now

$\Rightarrow s_1=5+s$

$\Rightarrow 20\times t-\frac{1}{2}gt^2 =5+3t$

$\Rightarrow 5t^2-17t+5=0$

$\Rightarrow t=\dfrac{17\pm \sqrt{17^2-4(5)(5)}}{2\times 5}$

$\Rightarrow t=\dfrac{17\pm 13.747}{10}$

$\Rightarrow t=0.3253\ s\ \text{and}\ t=3.07\ s$

There are two times when camera reaches the same level as balloon and the smaller time is associated with with the first one .

(b)When passenger catches the camera time is $t=0.3253\ s$

velocity is given by

$v=u+at$

$v=20-10\times 0.3253$

$v=16.747\ m/s$

and position of camera is same as of balloon so

Position is $=5+3\times 0.3253$

$=5.975\approx 6\ m$

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3 years ago

If you can walk 3 miles per hour, how much is that in meters per second?

deff fn [24]

To convert 3 miles per hour into m/s, first we have to convert miles in to meter and then hour in to second.

As $1 miles = 1.609344 km = 1.609344\times 10^3 m = 1609.3 m$ and $1 hour=60 minutes = 60\times 60= 3600s$

Therefore,

$3 miles/ h=\frac{3\times1609.3m}{3600s} =1.34 m/s$

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3 years ago

An object initially at rest experiences an acceleration of 9.8m/s2. How much time will it take it to achieve a velocity of 49m/s

Vlad1618 [11]

Answer:5seconds

Explanation:

initial velocity(u)=0

Final velocity(v)=49m/s

acceleration(a)=9.8m/s2

Time(t)=?

V=u+axt

49=0+9.8xt

49=9.8t

t=49/9.8

t=5seconds

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3 years ago

PRESS THE PHOTO NEED HELP!!! 30 POINTS

olasank [31]

1:-

$\\ \sf\longmapsto cos\Theta=\dfrac{B}{H}$

$\\ \sf\longmapsto cos\Theta=\dfrac{4}{5}$

2:-

$\\ \sf\longmapsto tan\Theta=\dfrac{P}{B}$

$\\ \sf\longmapsto Tan\Theta=\dfrac{3}{4}$

Key Notes:-

P denotes to Perpendicular.
B denotes to Base.
H denotes to Hypotenuse.

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3 years ago

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