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liq [111]
3 years ago
6

In lenzs law: If the current flow along the direction of deflection of the galvanometer, predict the direction of current in the

face of the coil closer to the bar magnet in steps 2 and 3.
Q2.If clockwise direction of current indicate south pole and counter clockwise indicates north of a magnet, predict the polarity of the face of the coil closer to the bar magnet in steps 2 and 3. what can u conclude from here​
Physics
1 answer:
sertanlavr [38]3 years ago
7 0

Answer:

this answer is only for points

Explanation:

Mark me as a brain list please

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A physician orders Humulin R 44 units and Humulin N 40 units qam and Humulin R 35 units ac evening meal subcutaneously. How many
jekas [21]

The question is incomplete, the concentration of qam and humulin is not given unless R is used concentration

Complete question:

A physician orders Humulin 50/50 44 units and Humulin N 40 units qam and Humulin R 35 units ac evening meal subcutaneously. How many total units of insulin are administered each morning?

Answer:

the total units of insulin admistered each morning

= 22 units of qam and humulin

Explanation:

given

44 units and Humnlin N

with concentration 50/100 = 1/2 = 0.5

∴ 44 × 0.5 ≈ 22 units in the morning

regular insulin administered each day

(22 + 35)units of qam and humulin

= 57units

5 0
3 years ago
Your friend decides to generate electrical power by rotating a 100,000 turn coil of wire around an axis in the plane of the coil
MakcuM [25]

Answer:

a) I=35mA

b) P=1.73W

Explanation:

a) The max emf obtained in a rotating coil of N turns is given by:

emf_{max}=NBA\omega

where N is the number of turns in the coil, B is the magnitude of the magnetic field, A is the area and w is the angular velocity of the coil.

By calculating A and replacing in the formula (1G=10^{-4}T) we get:

A=\pi r^2 =\pi(0.23m)^2=0.16m^2

emf_{max}=(100000)(0.3*10^{-4}T)(0.166m^2)(140\frac{rev}{s})=69.72V

Finally, the peak current is given by:

I=\frac{emf}{R}=\frac{69.72V}{1400\Omega}=49.8mA

b)

we have that

I_{rms}=\frac{I}{\sqrt{2}}=\frac{0.0498A}{\sqrt{2}}=0.035A

P_{rms}=I^2{rms}R=(0.035A)^2(1400\Omega)=1.73W

hope this helps!!

6 0
3 years ago
Ô tô chuyển động trên đường cong có bán kính R = 300(m). Nếu vận tốc ôtô tăng đều từ v1 =
kow [346]

Answer:

Mc ,12,4

Explanation:

7 0
2 years ago
An object weighs 30 N on Earth. A second object weighs 30 N on the Moon. Which has the greater mass?
andreev551 [17]

Answer:

The object on earth, because earth has a bigger amount of gravity than how much the moon has.

Explanation:

6 0
3 years ago
A sphere of plastic of radius = .100 m is completely immersed in water. The density of the plastic is 600 kg/m3. Since the plast
tekilochka [14]

To solve this problem we need to use the proportional relationships between density, mass and volume, together with Newton's second law.

The force can be described as

F = ma \rightarrow mg

Where,

m = Mass

g = Gravitational acceleration

At the same time the Density can be defined as

\rho = \frac{m}{V} \rightarrow m = \rho V

Where,

m = mass

V = Volume

Replacing the value of the mass at the equation of Force we have,

F = \rho V g

Since the difference between the two forces gives us the total Force then we have to

F_T = F_w - F_p

Where

F_w = Force of the water

F_p= Force of plastic

Therefore with the values for this force we have,

F_T = \rho_w Vg - \rho_p Vg

F_T = Vg(\rho_w - \rho_p)

F_T = (\frac{4}{3} \pi r^3) g(\rho_w - \rho_p)

F_T = (\frac{4}{3} \pi (0.1)^3) (9.8)(1000 - 600)

F_T = 16.412 N

Therefore the tension in the thread is 16.412N

3 0
3 years ago
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