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3 years ago

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In lenzs law: If the current flow along the direction of deflection of the galvanometer, predict the direction of current in the

face of the coil closer to the bar magnet in steps 2 and 3.
Q2.If clockwise direction of current indicate south pole and counter clockwise indicates north of a magnet, predict the polarity of the face of the coil closer to the bar magnet in steps 2 and 3. what can u conclude from here

1 answer:

sertanlavr [38]3 years ago

7 0

Answer:

this answer is only for points

Explanation:

Mark me as a brain list please

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An object is thrown upward with an initial speed of 18.5 m/s from a location 12.2 m above the ground. After reaching its maximum

siniylev [52]

Answer:

The speed of the object in the last instant prior to hitting the ground is -24.1 m/s

Explanation:

The equation for the position and velocity of the object will be:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height of the object at time t

v0 = initial velocity

y0 = initial height

g = acceleration due to gravity

t = time

v = velocity at time t

We know that at its maximum height, the velocity of the object is 0. We can obtain the time it takes the object to reach the maximum height and with that time we can calculate the maximum height:

v = v0 + g · t

0 = 18.5 m/s - 9.8 m/s² · t

-18.5 m/s / -9.8 m/s² = t

t = 1.89 s

Now,let´s find the max-height:

y = y0 + v0 · t + 1/2 · g · t²

y = 12.2 m + 18.5 m/s · 1.89 s + 1/2 ·(-9.8 m/s²) · (1.89 s)²

y = 29.7 m

Now, let´s see how much it takes the object to hit the ground:

In that instant, y = 0.

y = y0 + v0 · t + 1/2 · g · t²

0 = 29.7 m + 0 m/s · t - 1/2 · 9.8 m/s² · t² (notice that v0 = 0 because the object starts from its maximum height, where v = 0)

-29.7 m = -4.9 m/s² · t²

t² = -29.7 m / -4.9 m/s²

t = 2.46 s

Now, we can calculate the speed at t= 2.46 s, the instant prior to hitting the ground.

v = v0 + g · t

v = g · t

v = -9.8 m/s² · 2.46 s

v = -24.1 m/s

4 0

3 years ago

The only pictures we have of the Milky Way are from ____________________.

erastova [34]

Most pictures used as the milky way are actually just pictures of other galaxies (such as Andromeda) that we just figure are similar enough to ours.

<span>We can take a side ways photo of our own galaxy, but not a front view. </span>

3 0

3 years ago

In the human eye, the receptors that are responsible for our ability to see color are called ___

dusya [7]

The answer is A. Cones, as rods are not sensitive to color. :)

5 0

3 years ago

A metal wire 1.50 m long has a circular cross section of radius 0.32 mm and an end-to-end resistance of 90.0 Ohms. The metal wir

elixir [45]

Answer:

So after stretching new resistance will be 0.1823 ohm

Explanation:

We have given initially length of the wire $l_1=150m$

Radius of the wire $r_1=0.32mm=0.32\times 10^{-3}m$

Resistance of the wire initially $R_1=90ohm$

We know that resistance is equal to $R=\frac{\rho l}{A}$ ,here $\rho$ is resistivity, l is length and A is area

From the relation we can say that $\frac{R_1}{R_2}=\frac{l_1}{l_2}\times \frac{A_2}{A_1}$

Now length of wire become 6.75 m

Volume will be constant

So $A_1l_1=A_2l_2$

So $\pi \times (0.32)^2\times150=\pi \times r_2^2\times 6.75$

$r_2=1.508mm$

So $\frac{90}{R_2}=\frac{150}{6.75}\times \frac{1.508^2}{0.32^2}$

$R_2=0.1823ohm$

7 0

3 years ago

Calculate the frequencies corresponding to the wavelengths 500.00 nm and 500.10 nm. Use these to check the accuracy of equation

mel-nik [20]

Explanation:

It is given that,

Wavelength, $\lambda_1=500\ nm=5\times 10^{-7}\ m$

Wavelength, $\lambda_2=500.10\ nm=5.001\times 10^{-7}\ m$

We need to find the frequencies from corresponding wavelengths. The frequency of the light is given by :

$f=\dfrac{c}{\lambda}$

c is the speed of light

Frequency 1,

$f_1=\dfrac{c}{\lambda_1}$

$f_1=\dfrac{3\times 10^8\ m/s}{5\times 10^{-7}\ m}$

$f_1=6\times 10^{14}\ Hz$

Frequency 2,

$f_2=\dfrac{c}{\lambda_2}$

$f_1=\dfrac{3\times 10^8\ m/s}{5.001\times 10^{-7}\ m}$

$f_1=5.99\times 10^{14}\ Hz$

Hence, this is the required solution.

3 0

3 years ago