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3 years ago

What is the Physics Primer?

Physics

2 answers:

Elza [17]3 years ago

7 0

Answer:

A. a set of mathematically topics that are relevant to introductory physics.

Explanation:

The physics primer is not defined as the online comprehensive mathematics textbooks. It is the set of topics of mathematics which gives students trouble and remember.

Therefore, it is defined as the process of physics problem solving. So, mathematically skills are covered in physics course as a primer related success.

Therefore, it is a set of topics of mathematics that are relevent to introductory physics.

Dimas [21]3 years ago

5 0

Answer:

A. A set of mathematics topics that are relevant to introductory physics courses.

Explanation:

Physics Primer consists of tutorials, videos, and answers to specific questions, the main idea is to build a solid structure of math concepts for introductory physics. Another great thing about Physics Prime is that it helps students to visualize problems and solve them from different perspectives. The concepts built throughout the course can positively impact the result of the student especially if the course is taken before the physics introductory course.

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When you look at the light from distant stars you are really looking back in time explain what this means

Leona [35]

Answer: Stars are in space for very long time, much longer than that one night. You are looking back in time because those stars have been there for so long that it’s like looking back in time, to when those stars were there.

Explanation:

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3 years ago

Read 2 more answers

Nalah labels ten rats with the numbers 1 through 10. Then, she records how long it takes each rat to run through a maze. She fin

drek231 [11]

Answer:

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Explanation:

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3 years ago

What is the energy dissipated as a function of time in a circular loop of N turns of wire having a radius of r0 and a resistance

Snezhnost [94]

Explanation:

Let N be the number of turns in a circular loop having a radius of r₀ and a resistance R. The magnetic field is given by :

$B(t)=B_oe^{-\dfrac{t}{\tau}}$

The induced emf in the circular coil is given by :

$\epsilon=\dfrac{-d\phi}{dt}$

Where

$\phi=BA$

$\epsilon=N\dfrac{-d(BA)}{dt}$

$\epsilon=NAB_o\dfrac{-d(e^{-\dfrac{t}{\tau}})}{dt}$

$\epsilon=\dfrac{NAB_o}{\tau}e^{-t/\tau}$

Power dissipated is given by :

$P=\dfrac{\epsilon^2}{R}$

$P=\dfrac{(\dfrac{NAB_o}{\tau}e^{-t/\tau})^2}{R}$

$P=(\dfrac{NAB_o}{\tau})^2\dfrac{e^{-2t/\tau}}{R}$

Energy dissipated in the circuit is given by :

$E=\int\limits^T_0 {P.dt}$

$E=\int\limits^T_0 {(\dfrac{NAB_o}{\tau})^2\dfrac{e^{-2t/\tau}}{R}.dt}$

$E=\dfrac{1}{R}(\dfrac{NAB_o}{\tau})^2\int\limits^T_0 {e^{-2t/\tau}.dt}$

$E=\dfrac{(N\pi r_o^2B_o^2)^2}{2R}{\tau(e^{2t/\tau}-1)}{}$

Hence, this is the required solution.

7 0

3 years ago

How might spontaneous generation be possible in a reducing environment? Question options: The reducing environment was created b

melomori [17]

Please help me with the unit assessment i have no idea any of the answers

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3 years ago

What is the electrical consumption in KVA of a motor powered by a 3-phase, 60 Hz, 460 VAC supply that continuously draws 17 A

MrRa [10]

Answer:

15.34 kVA

Explanation:

A motor is a device that converts electrical energy into mechanical energy. It takes in electrical energy at the input and produce torque (motion) at the output.

The power consumption for a three phase motor is the product of voltage and current and √3. The √3 is because it is a three phase supply.

Hence Power (P) =√3 × voltage (V) × current (I)

P = √3 × V × I

Given that voltage (V) = 460 V, current (I) = 17 A. Hence:

P = √3 × V × I = √3 × 460 × 17 = 13544.64 VA

But 1000 VA = 1 kVA. Hence:

$P=13544.64\ VA*\frac{1\ kVA}{1000\ VA}=13.54\ kVA$

8 0

3 years ago