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3 years ago

What is the Physics Primer?

Physics

2 answers:

Elza [17]3 years ago

7 0

Answer:

A. a set of mathematically topics that are relevant to introductory physics.

Explanation:

The physics primer is not defined as the online comprehensive mathematics textbooks. It is the set of topics of mathematics which gives students trouble and remember.

Therefore, it is defined as the process of physics problem solving. So, mathematically skills are covered in physics course as a primer related success.

Therefore, it is a set of topics of mathematics that are relevent to introductory physics.

Dimas [21]3 years ago

5 0

Answer:

A. A set of mathematics topics that are relevant to introductory physics courses.

Explanation:

Physics Primer consists of tutorials, videos, and answers to specific questions, the main idea is to build a solid structure of math concepts for introductory physics. Another great thing about Physics Prime is that it helps students to visualize problems and solve them from different perspectives. The concepts built throughout the course can positively impact the result of the student especially if the course is taken before the physics introductory course.

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Read 2 more answers

You are riding on a roller coaster that starts from rest at a height of 25.0 m and moves down a frictionless track to a height o

irina [24]

Answer: 20.765 m/s

Explanation:

This problem can be solved by the conservation of energy principle, this means the initial energy $E_{o}$ must be equal to the final energy $E_{f}$ :

$E_{o}=E_{f}$ (1)

Where each energy is the sum of kinetic energy $K$ and potential energy $U$ :

$K_{o}+U_{o}=K_{f}+U_{f}$ (2)

Where:

$K_{o}=\frac{1}{2}mV_{o}^{2}$

Being $m$ your mass and $V_{o}=0 m/s$ your initial velocity, since the roller coaster sterted from rest.

$U_{o}=mgh_{o}$

Being $g=9.8 m/s^{2}$ the acceleration due gravity and $h_{o}=25 m$ your initial height

$K_{f}=\frac{1}{2}mV_{f}^{2}$

Being $V_{f}$ your final velocity

$U_{f}=mgh_{f}$

Being $h_{f}=3 m$ your final height

Rewritting (2):

$\frac{1}{2}mV_{o}^{2}+mgh_{o}=\frac{1}{2}mV_{f}^{2}+mgh_{f}$ (3)

$mgh_{o}=m(\frac{1}{2}V_{f}^{2}+gh_{f})$ (4)

Isolating $V_{f}$ :

$V_{f}=\sqrt{2g(h_{o}-h_{f})}$ (5)

$V_{f}=\sqrt{2(9.8 m/s^{2})(25 m-3 m)}$ (6)

Finally:

$V_{f}=20.765 m/s$ This is your spedd when you arrive at 3 m height

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4 years ago

How does gamma radiation differ from alpha or beta particle radiation?

earnstyle [38]

Answer:

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3 years ago