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shtirl [24]
3 years ago
15

A star has a surface temperature of 30,000 K. At what wavelength does the peak radiation occur? 100 nm

Physics
2 answers:
tangare [24]3 years ago
8 0
Use the displacement law, peak wavelength = 0.0029/T =0.0029/30000 = 97nm
Eva8 [605]3 years ago
8 0

Answer : Wavelength is 97 nm.

Explanation :

It is given that,

The surface temperature of a star, T=30,000\ K

We have to find the wavelength where the peak radiation occurs.

We can find the wavelength using Wein's displacement law i.e.

\lambda=\dfrac{b}{T}

b is the Wein's constant b=2.88\times 10^{-3}m.K

So, \lambda=\dfrac{2.88\times 10^{-3}\ m.K}{30,000\ K}

\lambda=9.6\times 10^{-8}\ m

or \lambda=97\ nm

Hence, the correct option is (b).        

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A marble rolls 269cm across the floor with a constant speed of in 44.1cm/s.
Marrrta [24]

Answer:

t = 6.09 seconds

Explanation:

Given that,

Speed, v = 44.1 cm/s

Distance, d = 269 cm

We need to find the time interval of the marble. Speed is distance per unit time.

v=\dfrac{d}{t}\\\\\implies t=\dfrac{d}{v}\\\\t=\dfrac{269\ \text{cm}}{44.1\ \text{cm/s}}\\\\t=6.09\ s

Hence, the time interval of the marble is 6.09 seconds.

6 0
3 years ago
Which element does not have the same number of electrons in its outermost shell as the other elements in its group?(1 point)
Setler79 [48]

Helium (He) does not have the same number of valence electrons as other elements in its group.

The periodic table is divided into groups with the last number of the group coinciding with the number of electrons that an element in the group has in its outermost or valence shell.

Helium is in group 18 which means that it should have the same number of valence electrons as :

  • Neon
  • Argon
  • Krypton
  • Xenon and,
  • Radon

Yet Helium only has 2 valence electrons. We can therefore conclusively say that Helium does not have the same number of valence electrons as other elements in its group.

<em>More information is available at brainly.com/question/20944279. </em>

4 0
3 years ago
Read 2 more answers
How much work is done by 0.070 m3 of gas, when the volume remains constant with pressure of 63 x 105 Pa?
stealth61 [152]

Answer:

W = 0 J

Explanation:

The amount of work done by gas at constant pressure is given by the following formula:

W = P\Delta V

where,

W = Work done by the gas

P = Pressure of the gas

ΔV = Change in the volume of the gas

Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:

W = P(0\ m^3)\\

<u>W = 0 J</u>

5 0
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valentina_108 [34]

Answer:b

Explanation:

6 0
2 years ago
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Murljashka [212]
You multiply the mass by the acceleration 82*7.5=615; that's what I would do
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