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3 years ago

10

Ik i already asked this but i need diff point of views

2 answers:

miskamm [114]3 years ago

8 0

If you need them to survive then you should take them. I take vitamins and pill, vitamins just by my parents want me to, and pills for a stomach ache that I sometimes get. I don’t take my vitamins all the time, and my pills I do only when I feel like I need them. I think you should take if you really need it. But it’s your choice and this is my opinion

salantis [7]3 years ago

5 0

Answer:

Is it prescribe to you?If so than yes if not then no need to

Explanation:

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What type of nonvisible light has a longer wavelength than the color red?

Kipish [7]

Answer:

i believe its blue

Explanation:

4 0

3 years ago

Why was it so important that the scientist investigating the atom be young and unattached to existing scientific thinking

tatiyna

Answer:

so they can find the aswer and not get hurt

Explanation:

7 0

3 years ago

What is the name of the functional group that is attached to this hydrocarbon?

Ksenya-84 [330]

Answer: alkyl halide

Explanation:

5 0

3 years ago

A solution was prepared by mixing 50.0 g

frez [133]

Answer:

4.78 %.

Explanation:

<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>

<em></em>

<em>mass % = (mass of solute/mass of solution) x 100.</em>

<em></em>

mass of MgSO₄ = 50.0 g,

mass of water = d.V = (0.997 g/mL)(1000.0 mL) = 997.0 g.

mass of the solution = mass of water + mass of MgSO₄ = 997.0 g + 50.0 g = 1047.0 g.

<em>∴ mass % = (mass of solute/mass of solution) x 100</em> = (50.0 g/1047.0 g) x 100 = <em>4.776 % ≅ 4.78 %.</em>

4 0

4 years ago

The Nernst equation at 20oC is:

saw5 [17]

Answer:

a. -58 millivolts

Explanation:

The given Nernst equation is:

$E_{ion} = 58 millivolts /z \Big[ log_{10} \Big( \dfrac{[ion]_{out}}{[ion]_{in}}\Big) \Big]}$

The equilibrium potential given by the Nernst equation can be determined by using the formula:

$E_{Cl^-} = \dfrac{2.303*R*T}{ZF} \times log \dfrac{[Cl^-]_{out}} {[Cl^-]_{in}}$

where:

gas constant(R) = 8.314 J/K/mol

Temperature (T) = (20+273)K

= 298K

Faraday constant F = 96485 C/mol

Number of electron on Cl = -1

$E_{Cl^-} = \dfrac{2.303*8.314*298} {(-1)*(96845)} \times log \dfrac{100} {10}$

$E_{Cl^-} = - 0.05814 \ volts$

$\mathsf{E_{Cl^-} = - 0.05814 \times 1000 \ milli volts}$

$\mathsf{E_{Cl^-} \simeq - 58\ milli volts}$

5 0

3 years ago