Which answer is a scientifically accurate description of velocity?
1 answer:
The boat traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.
Explanation:
Velocity is a physical quantity that describes the rate of change of displacement with time.
Velocity =
The quantity differs from speed in that it has both magnitude and direction.
From the options given above:
Displacement: The boat traveled in the north direction from the dock to a 200m mark.
Time taken: approximately less than 5 minutes was the duration of traveling.
This describes the boat's velocity accurately.
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Answer:
The maximum height covered is 3.25 m.
The horizontal distance covered is 9.81 m.
The total time in the air is 1.63 seconds.
Explanation:
The launch speed, .
Angle of launch with the horizontal,
So, the vertical component of the initial velocity,
.
The horizontal component of the initial velocity,
Let, t be the time of flight, to the horizontal distance covered
.
Not, applying the equation of motion in the vertical direction.
Where s is the displacement in time t, u is the initial velocity and a is the acceleration.
In this case, (from equation (i), s=0 (as the final height is same as the launch height) and
(negative sign is due to the downward direction).
seconds.
So, the total time in the air is 1.63 seconds.
From equation (i),
Total horizontal distance covered is
.
Now, for the maximum height, H, applying the equation of motion as
Here, v is the final velocity and v=0 (at the maximum height), and h=H.
So,
.
Hence, the maximum height covered is 3.25 m.
Answer:
a) the work (W) done during the process is -2043.25 kJ
b) the work (W) done during the process is -2418.96 kJ
Explanation:
Given the data in the question;
mass of water vapor m = 10 kg
initial pressure P₁ = 550 kPa
Initial temperature T₁ = 340 °C
steam cooled at constant pressure until 60 percent of it, by mass, condenses; x = 100% - 60% = 40% = 0.4
from superheated steam table
specific volume v₁ = 0.5092 m³/kg
so the properties of steam at p₂ = 550 kPa, and dryness fraction
x = 0.4
specific volume v₂ = v + xv
v₂ = 0.001097 + 0.4( 0.34261 - 0.001097 )
v₂ = 0.1377 m³/kg
Now, work done during the process;
W = mP₁( v₂ - v₁ )
W = 10 × 550( 0.1377 - 0.5092 )
W = 5500 × -0.3715
W = -2043.25 kJ
Therefore, the work (W) done during the process is -2043.25 kJ
( The negative, indicates work is done on the system )
b)
What would the work done be if steam were cooled at constant pressure until 80 percent of it, by mass, condenses
x₂ = 100% - 80% = 20% = 0.2
specific volume v₂ = v + x₂v
v₂ = 0.001097 + 0.2( 0.34261 - 0.001097 )
v₂ = 0.06939 m³/kg
Now, work done during the process will be;
W = mP₁( v₂ - v₁ )
W = 10 × 550( 0.06939 - 0.5092 )
W = 5500 × -0.43981
W = -2418.96 kJ
Therefore, the work (W) done during the process is -2418.96 kJ