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Marina86 [1]
3 years ago
6

What is the velocity (in m/s) of a 550 kg roller coaster cart at the bottom of the track if it started with 990,000 J of gravita

tional potential energy at the top of the track? Assume a frictionless surface.
Physics
1 answer:
sesenic [268]3 years ago
4 0

Answer:

60m/s

Explanation:

initial energy = final energy

g.p.e = k.e

k.e = 0.5 × mass × velocity²

g.p.e = 990000J as per Question

990000Nm = 0.5 × 550 × V²

V² = 3600

V = 60m/s

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The gas sample has now returned to its original state of 1.00 atm, 20.0 ∘c, and 1.00 l. what will the pressure become if the tem
steposvetlana [31]

At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

T1/P1 = T2/P2

P2 = T2 x P1 / T1

P2 = 473.15 x 1.00 / 293.15

<span>P2 = 1.61 atm</span>

3 0
3 years ago
Rainwater draining from a neighborhood street initially travels at 4 ft/s through a pipe with a cross-sectional area of 15.7 ft2
Fudgin [204]

Answer:

The  velocity  is v_2  =  0.96 \ ft/s

Explanation:

From the question we are told that

   The initial speed is  v_1  =  4 \ ft/s

   The  cross -sectional area of the first pipe is  A_1  =  15.7 \ ft

   The  cross -sectional area of the second pipe is A_2 =  65.4 \  ft

Generally from continuity equation we have that

     A_1 * v_1 =  A_2  * v_2

So  

     v_2  =  \frac{A_1 *  v_1  }{A_2 }

=>   v_2  =  \frac{15.7  *  4  }{65.4 }

=>   v_2  =  0.96 \ ft/s

6 0
3 years ago
Use the drop-down menus to complete the statement.
Nikitich [7]
Classics.

Resistance is equal to relation between voltage and current.

R = \frac{U}{I}

If we express current:

I = \frac{U}{R}

If current is in fact 0 then one of the quantities either voltage or resistance must be equal to zero. Since resistance cannot be equal 0, because that would violate mathematical law that states that division by zero is undefined the only logical conclusion is voltage.

So the answer should be C voltage and B zero.

Hope this helps!
8 0
3 years ago
Read 2 more answers
During a collision, a 63.9-kilogram driver of a car moving at 24 m/s is brought to rest by an inflating airbag in 1.2 seconds. W
kaheart [24]

Hi there!

We can use impulse for this situation:

I = Δp = mΔv

Impulse = Force × time, so:

I = 63.9(24) = 1533.6 Ns

Find force by dividing by time:

I/t = 1533.6/1.2 = 1278 N

7 0
2 years ago
A playground merry-go-round with a radius of 2.0 m and a rotational inertia of 100 kg m2 is rotating at 3.0 rad/s. A child with
vagabundo [1.1K]

Answer:

Explanation:

Conservation of angular momentum

The MGR originally has momentum

L = 100(3.0) = 300 kg•m²/s²

The child can be thought of as a point mass with I = mr²

When she jumps onto the rim of the MGR

300 = (100 + 22(2.0²)ω

ω = 300 / 188 = 1.5957... 1.6 rad/s

As she moves toward the center of the MGR, her moment of inertia goes to zero as her radius goes to zero.

The angular velocity when she reaches the center will again be 3.0 rad/s

8 0
3 years ago
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