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Marina86 [1]
2 years ago
6

What is the velocity (in m/s) of a 550 kg roller coaster cart at the bottom of the track if it started with 990,000 J of gravita

tional potential energy at the top of the track? Assume a frictionless surface.
Physics
1 answer:
sesenic [268]2 years ago
4 0

Answer:

60m/s

Explanation:

initial energy = final energy

g.p.e = k.e

k.e = 0.5 × mass × velocity²

g.p.e = 990000J as per Question

990000Nm = 0.5 × 550 × V²

V² = 3600

V = 60m/s

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With the same block-spring system from above, imagine doubling the displacement of the block to start the motion. By what factor
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Answer:

A)     K / K₀ = 4   b)     v / v₀ = 4

Explanation:

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in the problem it indicates that the displacement was doubled (x = 2xo)

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if we call

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3 0
3 years ago
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