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Marina86 [1]
3 years ago
6

What is the velocity (in m/s) of a 550 kg roller coaster cart at the bottom of the track if it started with 990,000 J of gravita

tional potential energy at the top of the track? Assume a frictionless surface.
Physics
1 answer:
sesenic [268]3 years ago
4 0

Answer:

60m/s

Explanation:

initial energy = final energy

g.p.e = k.e

k.e = 0.5 × mass × velocity²

g.p.e = 990000J as per Question

990000Nm = 0.5 × 550 × V²

V² = 3600

V = 60m/s

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Pseudoscience

Pseudoscience is made of up statements, beliefs or practices that claim to be scientific and factual but are not based in the scientific method.

5 0
3 years ago
Two charged particles are placed 2.0 meters apart. The first charge is +2.0 E-6 C, and the second charge is +4.0 E-6 C. What is
ipn [44]
F = kq1q2/r^2 

<span>q1 is first charge </span>
<span>q2 is second charge </span>
<span>k is 9 E9 </span>
<span>r is distance between them </span>

<span>F = (9E9)(2 E-6)(4 E-6)/2^2 = 0.018 N </span>

<span>A postive answer indicates a repulsive force</span>
4 0
3 years ago
Suppose two wagons, one with twice as much mass as the other, fly apart when a compressed spring that joins them is released. Th
sp2606 [1]

Answer:

The heavier wagon rolls 1/2 as fast as the lighter wagon.

Explanation:

When the compressed spring that joins them is released then the force acts on both wagons will be of equal magnitude but in the opposite direction. However as the mass of one wagon is twice that of other, so the acceleration  will become half of the heavier wagon in comparison with lighter one.

7 0
3 years ago
¿Cuánto tardará un automóvil, con movimiento uniforme, en recorrer una distancia de 195 Km si su velocidad es de 30Km/h.?
kykrilka [37]

Answer:

あなたのポイントを無駄にして申し訳ありませんが、あなたの質問がその言語を日本語にすることがわかりません

7 0
3 years ago
Two charges, one +Q and the other −Q, are held a distance d apart. Consider only points on the line passing through both charges
solong [7]

Answer:

a. d/2 mid-way between the charges.

b. d/2 mid-way between the charges.

Explanation:

(a) Find the location of all points, if any, where the electric potential is zero.

Since the charges are of equal magnitude and opposite charge and separated by a distance, d, the electric potential due to the +Q charge is V = kQ/x and that due to the -Q charge is V' = -kQ/(d - x) where x is the point of zero electric potential.

The potential is zero when  V + V' = 0, and this can only be midway between the charges. This is shown below

So, kQ/x + [-kQ/(d - x)] = 0

kQ/x - kQ/(d - x) = 0

kQ/x = kQ/(d - x)

1/x = 1/(d - x)

(d - x) = x

d = x + x

d = 2x

x = d/2 which is mid-way between the charges.

(b) Find the location of all points, if any, where the electric field is zero.

Since the charges are of equal magnitude and opposite charge and separated by a distance, d, the electric field due to the +Q charge is E = kQ/x² and that due to the -Q charge is E' = -kQ/(d - x)² where x is the point of zero electric field.

The electric field is zero when  E + E' = 0 and this can only be midway between the charges. This is shown below.

So, kQ/x² + [-kQ/(d - x)²] = 0

kQ/x² - kQ/(d - x)² = 0

kQ/x² = kQ/(d - x)²

1/x² = 1/(d - x)²

(d - x)² = x²

d - x = ± x

d = x ± x

d = x - x or x + x

d = 0 or 2x

d = 0 or d = 2x

Since d ≠ 0, d = 2x ⇒ x = d/2 which is midway between the charges.

4 0
3 years ago
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