What is the velocity (in m/s) of a 550 kg roller coaster cart at the bottom of the track if it started with 990,000 J of gravita
1 answer:
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Explanation:
It is given that,
Diameter of the peach pie, d = 9 inches
Radius of the pie, r = 4.5 inches
The tray is rotated such that the rim of the pie plate moves through a distance of 183 inches, d = 183 inches
Let is the angular distance that the pie plate has moved through.
It is given by :
Since, 1 radian = 57.29 degrees
Since, 1 radian = 0.159155 revolution
Hence, this is the required solution.
Answer: 1.51 km
Explanation:
<u>Coulomb's Law:</u> The electrostatic force between two charge particles Q: and Q2 is directly proportional to product of magnitude of charges and inversely proportional to square of separation distance between them.
Or,
Where Q1 and Q2 are magnitude of two charges and r is distance between them:
<u>Given:</u>
Q1 = Charge near top of cloud = 48.8 C
Q2 = Charge near the bottom of cloud = -41.7 C
Force between charge at top and bottom of cloud (i.e. between Q: and Q2) (F) = 7.98 x 10^6N
k = 8.99 x 109Nm^2/C^2
<u>So,</u>
Therefore, the separation between the two charges (r) = 1.51 km
Answer:
Explanation:
The equation for this is
where f is the frequency, v is the velocity, and lambda is the wavelength. Filling in:
and
which means that
the wavelength is 1.37 m, rounded to the correct number of significant digits.