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OLga [1]
3 years ago
5

If the wavelength (λ) of this wave is 0.012m, what is the speed (v) of this wave on graph A?

Physics
1 answer:
Natalka [10]3 years ago
7 0

Answer:

it would be 0.122 I think

Explanation:

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The surface is frictionless, so there is no frictional force acting on the ball. There are no other forces acting on the ball in the horizontal direction, so it's a uniform motion with constant speed. Therefore, the velocity of the ball will remain the same for the entire duration of the motion, and so after 5 seconds the velocity is still 15 m/s.
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4 years ago
A 2.5 kg block is launched along the ground by a spring with a spring constant of 56 N/m. The spring is initially compressed 0.7
Norma-Jean [14]

vf ^2 = kx^2/m = 56(0.75)^2 / 2.5 = 12.6


Therefore, v= 3.5 m/s.

7 0
3 years ago
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A plane travels 2.5 KM at an angle of 35 degrees to the ground, then changes direction and travels 5.2 km at an angle of 22 degr
Solnce55 [7]

Answer:

7.7 km 26°

Explanation:

The total x component is:

x = 2.5 cos(35°) + 5.2 cos(22°) = 6.87

The total y component is:

y = 2.5 sin(35°) + 5.2 sin(22°) = 3.38

The magnitude is:

d = √(x² + y²)

d = 7.7 km

The direction is:

θ = atan(y/x)

θ = 26°

5 0
3 years ago
Where is oceanic crust being formed?
Sever21 [200]
Oceanic crust is being formed it is because of the tectonic plates. Tectonic plates work because of volcanic eruption every time it will erupt the tectonic plates underground will have more pressure on magma, then below there will be a volcano thats why their is a volcano in ocean. The heat rises up then it will open, thats what we call divergent bounderies then their will be earthquakes form. Then another plate opens up and the crust is going down, it will stop if the volcano stops erupting because there is more lava left in volcano then it will go underwater and thats why oceanic crust is being formed.

#CarryOnLearning

Butbot na dili na tinuod ga timala ra ko ana
3 0
3 years ago
A box is dropped from a spacecraft moving horizontally at 27.0 m/s at a distance of 155 m above the surface of a moon. The rate
gavmur [86]

Answer:

a) 10.54 sec

b) 284.58 m

c) 29.406 m/s

d) 39.92 m/s

Explanation:

Given data:

velocity of spacecraft = 27.0 m/s

rate of free fall acceleration is 2.79 m/s^2

distance of moving aircraft from mooon surface is 155 m

a. from kinematic eqaution of motion we have

y = Vi\times t + (\frac{1}{2}) a\times t^2

where y = 155 m

           Vi = 0  as this relation  is for vertical motion, so the 27.0 m/s is not included

and a = 2.79 m/s^2.

Solving for t we get

t = 10.54 sec

b.

we know that V = \frac{d}{t}

d = v\times t

   = 27 \times 10.54 = 284.58 m

c.  from the kinematic formula

v = u + at

v = 0 + 2.79\times 10.57

v = 29.4066 m/a

d. v = \sqrt { 27^2 + 29.406^2}

     v = 39.92 m/s

4 0
3 years ago
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