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OLga [1]
3 years ago
5

If the wavelength (λ) of this wave is 0.012m, what is the speed (v) of this wave on graph A?

Physics
1 answer:
Natalka [10]3 years ago
7 0

Answer:

it would be 0.122 I think

Explanation:

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Explain how the fixed points are used when calibrating a thermometer. ​
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<u>Answer:</u>

First, the thermometer is dipped into boiling water, and the mercury inside the thermometer rises to a high level, called the boiling point. This level is then marked as 100°C. The thermometer is then dipped into melting ice, which causes the mercury level to fall to a point called the ice point. This point is then marked as 0°C. The length of the thermometer from the 0°C mark to the 100°C point is then divided into 100 equal sections, and the rest of the levels are marked accordingly.

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2 years ago
What is the half-life of an isotope that decays to 25% of its original activity in 70.8 hours?
loris [4]
Are there any options?
8 0
3 years ago
Which formula can be used to find the angle of the resultant vector has
nata0808 [166]
The diagram shows components that have been added together to form Rx and Ry. Rx and Ry are the components of the resultant vector.
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5 0
2 years ago
A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm2 , plate separation d = 9.00 mm and dielectric constant
PIT_PIT [208]

Answer:

9.96\cdot 10^{-10}J

Explanation:

The capacitance of the parallel-plate capacitor is given by

C=\epsilon_0 k \frac{A}{d}

where

ϵ0 = 8.85x10-12 C2/N.m2 is the vacuum permittivity

k = 3.00 is the dielectric constant

A=30.0 cm^2 = 30.0\cdot 10^{-4}m^2 is the area of the plates

d = 9.00 mm = 0.009 m is the separation between the plates

Substituting,

C=(8.85\cdot 10^{-12}F/m)(3.00 ) \frac{30.0\cdot 10^{-4} m^2}{0.009 m}=8.85\cdot 10^{-12} F

Now we can calculate the energy of the capacitor, given by:

U=\frac{1}{2}CV^2

where

C is the capacitance

V = 15.0 V is the potential difference

Substituting,

U=\frac{1}{2}(8.85\cdot 10^{-12}F)(15.0 V)^2=9.96\cdot 10^{-10}J

4 0
3 years ago
The power grid is the system that transfers electricity to homes and businesses. A power plant produces electricity. The output
sasho [114]

Answer: energy

Explanation: So the input and output of the power grid system is energy.

6 0
3 years ago
Read 2 more answers
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