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stira [4]
3 years ago
8

0.2 points

Physics
1 answer:
Nutka1998 [239]3 years ago
7 0
The answer is 2.6m/s2
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LW Hydraulic engineers in the United States often use, as a unit of volume of water, the acre-foot, defined as the volume of wat
ruslelena [56]

Answer:

volume of water is 1066.50 acre feet

Explanation:

given data

dia = 2 in = 0.166 feet

area = 26 km² = 26 × 247.105 acre = 6424.73 acre

to find out

volume of water

solution

we know volume of water is express as

volume = area × dia     ....................1

put here value in equation 1

volume = 6424.73 acre × 0.166 feet

volume = 1066.50

so volume of water is 1066.50 acre feet

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3 years ago
A baseball player hits a 140 g baseball with a force of 2800 N. What is the
Murljashka [212]
B because 2800 divide by 40 is 20
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3 years ago
A 45 kg wagon is being pulled with a rope that makes an angle of 38 degrees with the horizontal. The applied force is 410 N and
mel-nik [20]

Answer:

7.35m/s²

Explanation:

From the question we are not told what to find but we can as well find the acceleration of the wagon.

According to newton second law of motion

\sum F_x = ma_x\\Fm - Ff = ma_x\\Fm - \mu R = ma_x\\Fm- \mu mg = ma_x\\

Fm is the moving force = 410N

\mu is the coefficient of friction = 0.18

m is the mass = 45kg

g is the acceleration dur to gravity = 9.8m/s²

a is the acceleration of the wagon

Substitute the given data into the equation ang get ax

Fm- \mu mg = ma_x\\410 - (0.18)(9.8)(45) = 45a_x\\410 - 79.38 = 45a_x\\330.62 = 45a_x\\a_x = 330.62/45\\a_x = 7.35m/s^2\\

Hence the acceleration of the wagon is 7.35m/s²

8 0
3 years ago
Describe different types of force in nature at least five​
sineoko [7]

Weathering, Erosion,  deposition, acid rain, precipitation

Explanation:

3 0
3 years ago
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A flat coil of wire consisting of 20 turns, each with an area of 50 cm2, is positioned perpendicularly to a uniform magnetic fie
Nutka1998 [239]

Answer:

i = 0.5 A

Explanation:

As we know that magnetic flux is given as

\phi = NBA

here we know that

N = number of turns

B = magnetic field

A = area of the loop

now we know that rate of change in magnetic flux will induce EMF in the coil

so we have

EMF = NA\frac{dB}{dt}

now plug in all values to find induced EMF

EMF = (20)(50 \times 10^{-4})(\frac{6 - 2}{2})

EMF = 0.2 volts

now by ohm's law we have

current = \frac{EMF}{Resistance}

i = \frac{0.2}{0.40} = 0.5 A

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3 years ago
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