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fgiga [73]
3 years ago
6

If a gun is sighted to hit targets that are at the same height as the gun and 85 m away at the same height, how low, as a positi

ve number in meters, will the bullet hit if aimed directly at a target 180 m away
Physics
1 answer:
Alex3 years ago
7 0

If a gun is sighted to hit targets that are at the same height as the gun and 85 m away at the same height, how low, as a positive number in meters, will the bullet hit if aimed directly at a target 180 m away

The muzzle velocity of the bullet is 275 m/s

Answer:

y = -1.1109 m

Explanation:

Range = \frac{v^2sin2\theta}{g}

range = 85 m

velocity = 275 m/s

g = 9.8 m/s²

85 = \frac{(275)^2sin2 \theta}{9.8}

833=(275)^2sin2\theta

833= 75625sin2\theta

0.01101 =sin2 \theta

0.005505 =sin \theta

\theta =sin^{-1}(0.005505)

\theta = 0.3154^0

If the bullet is aimed at a target 180 m, time required to travel 180 m with horizontal component will be;

t=\frac{180}{275cos0.3154}

t = 0.6546 sec

To determine, how low as a positive number in meters.

y=vyt-\frac{gt^2}{2}

y = 275 sin(0.3154)*(0.6546)- \frac{9.8*(0.6546)^2}{2}

y = 0.9909 - 2.1018

y = -1.1109 m

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