If the near-point distance of the jeweler is 22.0 cm, and the focal length of the magnifying glass is 7.70 cm, find the angular
1 answer:
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The formula your looking for is Vf = Vi + A (T)
Vf = Velocity Final
Vi = Velocity Initial
A = Acceleration
T = Time
Our Initial Velocity is 15m/s. That’s our starting point.
Acceleration is -3m/s. It’s negative because we’re slowing down
We know that the cyclist comes to a complete stop, which means the Final Velocity is 0
In order to solve this with the equation. We need three of the four variables. We just don’t know time. So our setup is -
0 = 15-3(T)
Then you solve
Vf = Velocity Final
Vi = Velocity Initial
A = Acceleration
T = Time
Our Initial Velocity is 15m/s. That’s our starting point.
Acceleration is -3m/s. It’s negative because we’re slowing down
We know that the cyclist comes to a complete stop, which means the Final Velocity is 0
In order to solve this with the equation. We need three of the four variables. We just don’t know time. So our setup is -
0 = 15-3(T)
Then you solve
Answer:
Low satellite has high orbital velocity
Explanation:
let v be the orbital speed of the satellite orbiting at a height h is given by
where, M be the mass of planet, r be the radius of planet and h be the height of planet from the surface of planet.
here we observe that more be the height lesser be the orbital velocity.
So, a satellite which is at low height has high orbital velocity.