Terrence connects several lightbulbs in a parallel circuit. Electricity flows through the circuit, and all the bulbs light up.
1 answer:
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Answer:
Part A
The intensity is
Part B
The intensity is
Explanation:
From the question we are told that
The intensity of the light detected by first eye is
Now at initial state according the question the light ray is perpendicular to the eye so it means that it is at 90° the eye
Now the first question is to obtain the intensity the first eye (the first in this case is the one focused on the light )would detect when the head is rotated by 20° its previous orientation
This is mathematically evaluated as
Now the second question is to obtain the intensity the first eye (the first eye in this case is the one that is not focused on the light )would detect when the head is rotated by 20° its previous orientation
Now in this case the angle between the eye and the light is 90-20 = 70°
So
Answer:
fo = 378.52Hz
Explanation:
Using Doppler effect formula:
where
f' = 392 Hz
C = 340m/s
Vb = 20m/s
Va = 31m/s
Replacing these values and solving for fo:
fo = 378.52Hz
Answer:
The average current is 19.567 A
Solution:
As per the question:
Charge, Q =
Time, t =
Now,
We know that current is constituted by the rate of transfer of the charge per unit time. Thus we can write:
I = (1)
Now, the charge that was transferred is 86 % of the original value.
Therefore,
We replace Q by 0.86Q in eqn (1):
I =