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andreev551 [17]
3 years ago
9

Terrence connects several lightbulbs in a parallel circuit. Electricity flows through the circuit, and all the bulbs light up. 

  What will happen if Terrence removes lightbulb number 2
Physics
1 answer:
Ganezh [65]3 years ago
7 0
Light bulb number two would go out and the others would stay lit because it is parallel and not a series circuit that if you remove one from it they all go out. 
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how do i.... Find the angle between each pair of vectors below. (1 point each) a. a = 2x + 3y a = 4x + 2y
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Recall that the dot product between two vectors \mathbf a and \mathbf b satisfies

\mathbf a\cdot\mathbf b=\|\mathbf a\|\|\mathbf b\|\cos\theta

where \|\mathbf x\| denotes the norm of a vector \mathbf x, and \theta is the angle between the two vectors.

So if \mathbf a=(2,3) and \mathbf b=(4,2), then

(2,3)\cdot(4,2)=\|(2,3)\|\|(4,2)\|\cos\theta

\implies2\cdot4+3\cdot2=\sqrt{2^2+3^2}\sqrt{4^2+2^2}\cos\theta

\implies\cos\theta=\dfrac{14}{\sqrt{13}\sqrt{20}}

\implies\theta\approx29.7^\circ

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CaCO3 is the product of this reaction
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4 years ago
If u shine a light of frequency 375Hz on a double slit setup, and u measure the slit separation to be 950nm and the screen dista
xxMikexx [17]

Answer:

Y = 3.39 x 10⁶ m

Explanation:

We will use Young's Double Slit formula here:

Y = \frac{\lambda L}{d}

where,

Y = Fringe spacing = ?

λ = wavelength = \frac{speed\ of\ light}{frequency} = \frac{3\ x\ 10^8\ m/s}{375\ Hz} = 8 x 10⁵ m

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d = slit separation = 950 nm = 9.5 x 10⁻⁷ m

Therefore,

Y = \frac{(8\ x\ 10^5\ m)(4.03\ x\ 10^{-6}\ m)}{9.5\ x\ 10^{-7}\ m}

<u>Y = 3.39 x 10⁶ m</u>

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Hope this helps!
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4 years ago
Read 2 more answers
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