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Jobisdone [24]
3 years ago
10

In the molecule, HCl, the __atom pulls more on the bonded pair of electrons, creating a dipole

Chemistry
2 answers:
Anastaziya [24]3 years ago
6 0
I’m pretty sure it’s chlorine!
GalinKa [24]3 years ago
4 0
You should download the app tutor.com to help you
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Which component of a plant makes the cell walls around plant cells tough and allows branches, stems, and leaves to be strong
Vsevolod [243]
<h3><u>Answer;</u></h3>

Cellulose

<h3><u>Explanation</u>;</h3>
  • Cellulose is a polysaccharide and the most abundant organic compound on the Earth's surface.
  • <em><u>It  is an important organic molecule due to its strong structure which provides a wide variety of functions. </u></em>
  • <em><u>Cellulose is a major component of tough cell walls that surround plant cells and is what makes plant stems, leaves, and branches very  strong.</u></em>
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8 0
3 years ago
Name: _________________ Temperature o fwater_25_degreecent.YOU MUST SHOW ALL CALCULATIONS TO RECEIVE CREDIT FOR THEM! DATA ANALY
Anton [14]

Answer:

1. 0.02 M

2. 0.01 M

3. 4×10⁻⁶

Explanation:

We know that V₁S₁ = V₂S₂

1.

Concentration of HCl = 0.05 M

end point comes at = 10 ml

So, concentration of OH⁻(aq) = [OH⁻(aq)] ⇒ (0.05 × 10) ÷ 25 ⇒ 0.02 M

2.

2mol of OH⁻(aq) ≡ 1 mole of Ca²⁺(aq)

[Ca²⁺] = 0.02 ÷ 2 = 0.01 M

3.

K_{sp} = [Ca²⁺(aq)] [OH⁻(aq)]²

Ca(OH)₂ (aq) ⇄ Ca²⁺ (aq) + 2OH⁻ (aq)

K_{sp} = [0.01 × (0.02)²] = 4×10⁻⁶

4.

If reaction is exothermic which means heat energy will get evolved as a result temperature of the reaction media will get increased during the course of the reaction. If temperature is externally increased, the reaction will go backward to accumulate extra heat energy.

5.

K_{sp} value describes the solubility of a particular ionic compound. The higher the K_{sp} value, the higher the Solubility will be.

6.

This may be due to uncommon ion effect. The process of other ions (K⁺ or Na⁺) may increase the solubility

4 0
3 years ago
I need help please!!!!!!!!!!!!!!!!!
AleksAgata [21]

Answer:I think its both

Explanation:

7 0
3 years ago
2. Carbon-11 is a radioactive isotope of carbon. Its half-life is 10 minutes.
Annette [7]
It’s probably probably 01/16 because of the other number don’t make sense except that one
5 0
3 years ago
Calculate the concentration of formate in a 100mm solution of formic acid at ph 4.15. The pka for formic acid is 3.75
MissTica

The molarity of formic acid is 100 mM or 100\times 10^{-3}M. The dissociation reaction of formic acid is as follows:

HCOOH\leftrightharpoons HCOO^{-}+H^{+}

The expression for dissociation constant of the reaction will be:

K_{a}=\frac{[HCOO^{-}][H^{+}]}{[HCOOH]}

Rearranging,

[HCOO^{-}]=\frac{K_{a}[HCOOH]}{[H^{+}]}

Here, pH of solution is 4.15 thus, concentration of hydrogen ion will be:

[H^{+}]=10^{-pH}=10^{-4.15}=7.08\times 10^{-5}M

Similarly, pK_{a}=3.75 thus,

[K_{a}=10^{-pK_{a}}=10^{-3.75}=1.78\times 10^{-4}M

Putting the values,

[HCOO^{-}]=\frac{(1.78\times 10^{-4}M)(100\times 10^{-3}M)}{(7.08\times 10^{-5}M}=0.2511 M

Therefore, the concentration of formate will be 0.2511 M.

4 0
3 years ago
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