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viktelen [127]
3 years ago
12

17. Overall the drop in reduction potential from NADH to water is equivalent to the energy needed to synthesize six or seven mol

ecules of ATP, yet only about 2.5 molecules of ATP are actually synthesized? How does this apparent thermodynamic inefficiency allow ATP synthesis to be achieved? What would happen if the system were 100% efficient?
Chemistry
1 answer:
Vesnalui [34]3 years ago
8 0

Answer:

The ATP synthesis is achieved by the generation of proton motive force(PMF).

Explanation:

The proton motive force is generated by the transport of electrons from intermembrane space to matrix of mitocondria. The proton motive force is utilized by FO F1  ATPase to generate ATP from the phosphorylation of ADP and inorganic phosphate(Pi).

       If the system were 100% efficient then 64 molecules of of ATP can be generated from the complete oxidation of 1 molecule of glucose by aerobic respiration.

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It would be turned back to liquid 

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Choose specific acid-base conjugate pairs to make the following buffers: (a) pH ≈ 3.5;
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Our \ goal \ here\  is \ to \ find \ an \ acid-base \ conjugate \ pair \ that \ have \a \\\$pK_a-p H$. This is because we assume that the acid-base conjugate pair have an equal concentration to be considered an effective buffer.

$$p H-p K_a+\log \frac{\left[A^{-}\right]}{[H A]}$$

$$Where $\left[A^{-}\right]-[H A]$, so $\log \frac{\left[A^{-}\right]}{[H A]}-\log 1-0_{\text {so ... }}$$$

pH-pKa

$$Solve for $K_a$.$$

$$\begin{aligned}p H-p K_a &--\log K_a \\K_a &-10^{-p H} \\&-10^{-3.5} \\K_a &-3.2 \times 10^{-4}\end{aligned}$$

$$The nearest pairs are $\mathrm{HCOCOOH} / \mathrm{HCOCOO}^{-}$with a $\mathrm{K}_{\mathrm{a}}-3.5 \times 10^{-4}$,

$\mathrm{HOCH}_2 \mathrm{CH}(\mathrm{OH}) \mathrm{COOH} / \mathrm{HOCH}_2 \mathrm{CH}(\mathrm{OH}) \mathrm{COO}^{-}$with a $\mathrm{K}_{\mathrm{a}}-2.9 \times 10^{-4}$, and

$\mathrm{CH}_3 \mathrm{COOC}_6 \mathrm{H}_4 \mathrm{COOH} / \mathrm{CH}_3 \mathrm{COOC}_6 \mathrm{H}_4 \mathrm{COO}^{-}$with a $\mathrm{K}_a-3.6 \times 10^{-4}$. We can also check for the $\mathrm{K}_b$. First, solve for $p K_b$ then the $K_b$ -

$$\begin{aligned}p K_w &-p K_b+p K_a \\p K_b &-p K_w-p K_a \\&-14-3.5 \\p K_b &-10.5 \\p K_b &--\log K_b \\K_b &-10^{-p K_b} \\&-10^{-10.5} \\K_b &-3.2 \times 10^{-11}\end{aligned}$$

There \ are\  no \ pairs \ near \  this \  $K_b$ value.

<h3>What is a conjugate acid and base pair?</h3>

An acid-base pair that differs by one proton is referred to as a conjugate pair. A conjugate acid-base pair is a pair of substances that can both absorb and donate hydrogen ions to one another. A proton is added to the compound to create the conjugate acid, and a proton is taken out to create the conjugate base. When a proton is supplied to a base, a conjugate acid is created, and vice versa when a proton is taken away from an acid, a conjugate base is created.

To learn more about conjugate acid and base pair, visit;

brainly.com/question/10468518

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4 0
2 years ago
What is the valence electron for magnesium 2+​
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Answer:

two valence electrons

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4 0
3 years ago
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How many grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C?
jolli1 [7]

Answer:

22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C

Explanation:

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law:

P * V = n * R * T

where R is the molar constant of the gases and n the number of moles.

In this case you know:

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Replacing:

7.5 atm* 2.3 L=n*0.082 \frac{atm*L}{mol*K} *297K

Solving:

n=\frac{7.5 atm* 2.3 L}{0.082 \frac{atm*L}{mol*K} *297K}

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Knowing that oxygen gas is a diatomic gas of molecular form O₂ and its mass is 32 g / mole, you can apply the following rule of three: if 1 mole contains 32 grams, 0.708 moles, how much mass will it have?

mass=\frac{0.708 moles*32 grams}{1mole}

mass= 22.656 grams

<u><em>22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C</em></u>

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Coefficients are used here to balance the number of elements in the products and reactants. Coefficients are numbers that are placed in front of a chemical formulas in an equation. Hope it's useful.
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