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Andru [333]
3 years ago
7

Explain the difference between biotic and abiotic

Chemistry
1 answer:
Paladinen [302]3 years ago
7 0
Biotic are living organisms and abiotic are non living things such as rocks water soil
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What word chemical equation describes Cavendish’s experiment with zinc?
LiRa [457]
The chemical reaction of Cavendish involving zinc would be a reaction between hydrochloric acid and zinc yielding zinc chloride and hydrogen gas. The balanced chemical equation would be:

2Zn + 2HCl = 2ZnCl + H2

This is an example of a single replacement reaction where zinc replaces hydrogen in the acid molecule.
3 0
3 years ago
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The process of breaking down Glucose and using the energy stored in that molecule for cellular function is known as_____.
Katyanochek1 [597]

Answer:

Cellular respiration.

Explanation:

Through the process of cellular respiration, the energy in food is converted into energy that can be used by the body's cells. During cellular respiration, glucose and oxygen are converted into carbon dioxide and water, and the energy is transferred to ATP.

3 0
3 years ago
A certain reaction is thermodynamically favored at temperatures below 400. K, but it is not favored at temperatures above 400. K
Ilya [14]

Answer:

-0.050 kJ/mol.K

Explanation:

  • A certain reaction is thermodynamically favored at temperatures below 400. K, that is, ΔG° < 0 below 400. K
  • The reaction is not favored at temperatures above 400. K, that is. ΔG° > 0 above 400. K

All in all, ΔG° = 0 at 400. K.

We can find ΔS° using the following expression.

ΔG° = ΔH° - T.ΔS°

0 = -20 kJ/mol - 400. K .ΔS°

ΔS° = -0.050 kJ/mol.K

8 0
3 years ago
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can someone solve me some papers I don't have time and I need to submit today please I will make you brilliant ​
dem82 [27]

Answer:

submit the papers onto this platform and we will try to help out.

6 0
3 years ago
What volume in litres will 38gr of F2 occupy at 0.999 bar and 273 K
FrozenT [24]

Answer:

V=22.68L

Explanation:

Hello,

In this case, we use the ideal gas equation to compute the volume as shown below:

PV=nRT\\\\V=\frac{nRT}{P}

Nonetheless we are given mass, for that reason we must compute the moles of gaseous fluorine (molar mass: 38 g/mol) as shown below:

n=38 g *\frac{x}{y}  \frac{1mol}{38 g} =1mol

Thus, we compute the volume with the proper ideal gas constant, R:

V=\frac{1mol*0.083\frac{bar*L}{mol*K}*273K}{0.999bar} \\\\V=22.68L

Best regards.

7 0
3 years ago
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