<span>When M(OH)2 dissolves we have
M(OH)2 which produces M2+ and 2OHâ’
pH + pOH=14
At ph =7; we have
7+pOH=14
pOH=14â’7 = 7
Then [OHâ’]=10^(â’pOH)
[OH-] = 10^(-7) = 1* 10^(-7)
At ph = 10. We have,
pOH = 4. And [OH-] = 10^(-4) = 1 * 10^(-4)
Finally ph = 14. We have, pOH = 0
And then [OH-] = 10^(-0) -----anything raised to zero power is 1, but (-0)...
So [OH-] = 1</span>
Answer:
Standardisation is used to determine the concentration of a volumetric solution in order to achieve accurate and reliable titration results
Answer:
strength and vitality required for sustained physical or mental activity
Explanation:
Answer:
pH = 1.33
Explanation:
Because HCl is a strong acid, each mole of HCl will completely dissociate into H⁺ and Cl⁻ species.
Now we calculate the molar concentration (molarity) of H⁺:
- Molarity = moles / volume
(750 mL ⇒ 750 / 1000 = 0.750 L)
- Molarity = 0.035 moles / 0.750 L
Then we calculate the pH of the solution:
Because potassium is more reactive than hydrogen
