All categories

3 years ago

An alloy is a mixture that has

Chemistry

2 answers:

defon3 years ago

8 0

Answer:

an alloy is a mixture of elements that has metallic properties

Explanation:

labwork [276]3 years ago

3 0

Alloys can be a mixture of two metals, or two or more elements, in which one of them is a metal. An alloy may be a solid solution of mental elements! :)

You might be interested in

22. A flask containing 450 mL of 0.50 M H2SO4 was accidentally knocked to the floor. How many grams of NaHCO, do you need to put

Dvinal [7]

Answer: The correct answer is Option D.

Explanation:

To calculate the moles of a solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}\text{Volume of solution (in L)}}$

We are given:

Volume of sulfuric acid = 450mL = 0.45 L (Conversion factor: 1 L = 1000 mL)

Molarity of the solution = 0.5 moles/ L

Putting values in above equation, we get:

$0.5mol/L=\frac{\text{Moles of sulfuric acid}}{0.45L}\\\\\text{Moles of sulfuric acid}=0.225mol$

For the given chemical reaction:

$H_2SO_4(aq.)+2NaHCO_3(aq.)\rightarrow Na_2SO_4(aq.)+2H_2O(l)+2CO_2(g)$

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of sodium bicarbonate.

So, 0.225 moles of sulfuric acid will react with = $\frac{2}{1}\times 0.225=0.45mol$ of sodium bicarbonate

To calculate the mass of sodium bicarbonate, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of sodium bicarbonate = 0.45 moles

Molar mass of sodium bicarbonate = 84.007 g/mol

Putting values in above equation, we get:

$0.45mol=\frac{\text{Mass of sodium bicarbonate}}{84.007g/mol}\\\\\text{Mass of sodium bicarbonate}=38g$

Hence, the correct answer is Option D.

7 0

3 years ago

Write out the word equations for these reactions. ) Hydrogen reacts with oxygen to form water.

ale4655 [162]

Answer:

H2O

Explanation:

PLS MARK ME TO THE BRAINLIST

4 0

3 years ago

The green light emitted by a stoplight has a wavelength of 505 nm. What is the frequency of this photon? (c = 3.00 × 10⁸ m/s).

Kitty [74]

Answer:

5.9405*10^14 Hz

Explanation:

Remember the equation c=v*λ

v=frequency

λ=wavelength

By manipulating the equation, we can get it in terms of frequency:

c/λ=v

Now convert wavelength to meters (1nm=m*10^-9)

5.05*10^-7m (2 decimal places were shifted to make the number between 1-10, hence the -7 exponent)

Use the manipulated equation:

(3.00*10^8)/(5.05*10^-7), which yields:

5.9405*10^14 Hz (or s^-1)

6 0

3 years ago

A sample of an element has a volume of 78.0 mL and a density of 1.85 g/mL. What is the mass in grams of the sample?

abruzzese [7]

Hey there!:

density = 1.85 g/mL

volume = 78.0 mL

Mass = ??

therefore:

D = m / V

1.85 = m / 78.0

m = 1.85 x 78.0

m = 144.3 grams

Hope this helps!

7 0

3 years ago

Consider these three titrations: (i) the titration of 25.0 mL of a 0.100 M monoprotic weak acid with 0.100 M NaOH (ii) the titra

Setler79 [48]

Complete Question:

Consider these three titrations: (i) the titration of 25.0 mL of a 0.100 M monoprotic weak acid with 0.100 M NaOH (ii) the titration of 25.0 mL of a 0.100 M diprotic weak acid with 0.100 M NaOH (iii) the titration of 25.0 mL of a 0.100 M strong acid with 0.100 M NaOH. Which statement is most likely to be true?

(a) All three titrations require the same volume of NaOH to reach their first equivalence point.

(b) All three titrations have the same initial pH.

Answer:

(a) All three titrations require the same volume of NaOH to reach their first equivalence point.

Explanation:

(i) the titration of 25.0 mL of a 0.100 M monoprotic weak acid with 0.100 M NaOH

number of moles of acid = $\frac{25}{1000} dm^{3} * 0.1 M$ = 0.0025 moles

ii) the titration of 25.0 mL of a 0.100 M diprotic weak acid with 0.100 M NaOH

number of moles of acid = $\frac{25}{1000} dm^{3} * 0.1 M$ = 0.0025 moles

(iii) the titration of 25.0 mL of a 0.100 M strong acid with 0.100 M NaOH

number of moles of acid = $\frac{25}{1000} dm^{3} * 0.1 M$ = 0.0025 moles

Therefore, all the acids require the same number of moles of NaOH to reach their first equivalence points

Note that the concentration of the base NaOH are also the same, therefore the volume of NaOH required to reach equivalence point would also be the same for all the three titrations.

All three titrations don't have the same initial and equivalence point pH because they all have different acidic properties.

6 0

4 years ago

Read 2 more answers