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vazorg [7]
3 years ago
15

The direction of an electric field is the direction (5 points) a negative test charge will move in the field a positive test cha

rge will move in the field either a positive or negative test charge will move in the field the test charge may be either negative or positive
Physics
1 answer:
svet-max [94.6K]3 years ago
4 0

Answer:

a positive test charge will move in the field

Explanation:

The direction of an electric field corresponds to the direction of motion of a positive test charge in the electric field. In fact:

- the electric field produced by a positive charge points outwards the charge --> this is because when a positive test charge is placed in this field, it will feel a repulsive force (because two positive charges repel each other), so it will move away from the positive charge that produces the field

- the electric field produced by a negative charge points towards the charge  itself--> this is because when a positive test charge is placed in this field, it will feel an attractive force (because a positive and a negative charge attract each other), so it will move toward the negative charge that produces the field.

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in as small room fan of rating 50 watt is used for 10hrs 2bulb of rating 10v are used for 8hrs daily.calculate monthly. electric
Pie

Answer:

The electric bill for June is Rs198000

Explanation:

Convert volt to watt, but in order to do so I need to know the amps and since it is not provided I converted if the amps was 1.

I multiple 50 with 10 then  with 30 so I know how much watt the fan takes at June.

Since there are 2 light bulb I multiple 10 with 2 than with 8 than with 30.

15000 watts for the fan,

4800 watts for light bulb,

add them and then times it by 10.

Rs198000

4 0
2 years ago
!! Offering 50 points !!
Evgesh-ka [11]

Answeryes they are the same

Explanation:

0.5-0.5=10 is gotta be sorry if its wrong

8 0
3 years ago
Read 2 more answers
A bicycle tire is spinning counterclockwise at 2.70 rad/s. During a time period Δt = 1.50 s, the tire is stopped and spun in the
Andru [333]

Answer:

Δω = -5.4 rad/s

αav = -3.6 rad/s²

Explanation:

<u>Given</u>:

           Initial angular velocity = ωi = 2.70 rad/s

           Final angular velocity = ωf = -2.70 rad/s (negative sign is  

           due to the movement in opposite direction)

           Change in time period = Δt = 1.50 s

<u>Required</u>:

           Change in angular velocity = Δω = ?

           Average angular acceleration = αav = ?

<u>Solution</u>:

          <u>Angular velocity (Δω):</u>

               Δω = ωf - ωi

               Δω = -2.70 - 2.70

               Δω = -5.4 rad/s.

          <u> Average angular acceleration (αav):</u>

               αav = Δω/Δt

               αav = -5.4/1.50

              αav = -3.6 rad/s²

Since, the angular velocity is decreasing from 2.70 rad/s (in counter clockwise direction) to rest and then to -2.70 rad/s (in clockwise direction) so, the change in angular velocity is negative.

7 0
2 years ago
Read 2 more answers
Because energy is conserved, the “lost” energy has actually been changed into other forms. Looking at the two sleds, what effect
Shkiper50 [21]

Answer:

The answer is the kinetic energy of sled B after it crash is 6439j.

3 0
2 years ago
Please help me guys never mind the calculations ​
vlada-n [284]

The shape is connected in parallel so;

5.1) Ans;

\frac{1}{R}  =  \frac{1}{R1} +  \frac{1}{R2}   \\  \frac{1}{R}  =  \frac{1}{2}  +  \frac{1}{3}  \\  \frac{1}{R}  =  \frac{3 + 2}{6}  =  \frac{5}{6}  \\ R =  \frac{6}{5}  = 1.2 \:  \: ohm

5.2) Ans;

\frac{1}{R}  =  \frac{1}{R1} +  \frac{1}{R2}   \\  \frac{1}{R}  =  \frac{1}{8}  +  \frac{1}{10}  \\  \frac{1}{R}  =  \frac{5 + 4}{40}  =  \frac{9}{40}  \\ R =  \frac{40}{9}  = 4.4 \:  \: ohm

I hope I helped you^_^

7 0
2 years ago
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