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scZoUnD [109]
3 years ago
8

An oil film with refractive index 1.48 and thickness 290 nm is floating on water and illuminated with white light at normal inci

dence. What is the wavelength of the dominant color in the reflected light?
Physics
1 answer:
VikaD [51]3 years ago
8 0

Answer:

572.3 nm

Explanation:

n_{oil} = refractive index of the oil film = 1.48

t_{oil} = thickness of the oil film = 290 nm

\lambda = wavelength of the dominant color

m = order

Using the equation

2 n_{oil} t_{oil} = (m + 0.5) \lambda

For m = 0

2 (1.48) (290) = (0 + 0.5) \lambda

\lambda = 1716.8 nm

For m = 1

2 (1.48) (290) = (1 + 0.5) \lambda

\lambda = 572.3 nm

For m = 2

2 (1.48) (290) = (2 + 0.5) \lambda

\lambda = 343.4 nm

Hence the dominant color wavelength is 572.3 nm

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A 60-Hz single-phase transformer with capacity of 150 kVA has the following parameters: RP = 0.35 Ω RS = 0.002 Ω Rc = 5.2 kΩ XP
worty [1.4K]

Answer:

Explanation:

Total Resistance, Rt = (0.35 + 0.002 + 5200 + 0.5 + 0.008 + 1100) = 6300 ohms      

a) Capacity of transformer, Pt = 150KVA = 150,000 W

Input Voltage, Vp = 2.8 KV = 2800 V

Current, Ip = 150000/2800 = 53.57 A

Input impedance, Zp = Vp/Ip = 2800/5357 = 52.27 ohms

b) i)   Input current = 53.57 A

ii) Voltage, V = Ip * Rt = 53.57 X 6300 = 337.5 KV

iii) Power, P = I² * Rt = (53.57)² X 6300 = 18.08 MW

iv) Power factor = 0.83

8 0
3 years ago
Please help with this science question and please explain if you can! I'm so confused
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Question 5 of 20 An apple with a mass of 0.15 kg rests on the edge of a desk 0.65 m above the floor. Given that the acceleration
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2 years ago
Johnson is dragging a bag on a ice surface. He pulls on the strap with a force of 112 N at an angle of 45° to the horizontal to
Nady [450]

Answer with Explanation:

We are given that

Force=F=112 N

\theta=45^{\circ}

Distance,s=84 m

Time, t=3.33 minutes

We have to find the work done by Johnson on the bag and the power generated by Johnson.

Work done, W=Fscos\theta

Using the formula

Work done, W=112\times 84cos45=6652.46 J

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Using 1 minute=60 s

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