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ICE Princess25 [194]
3 years ago
5

" when striking, the pike, a predatory fish, can accelerate from rest to a speed of 4.0 m/s in 0.11 s."

Physics
1 answer:
Kipish [7]3 years ago
4 0
In an uniform accelerated motion, the distance covered by the fish is given by:
S= \frac{1}{2}at^2
where
a is the acceleration
t is the time

The acceleration is equal to the increase in speed of the fish divided by the time taken:
a= \frac{v_f-v_i}{t}= \frac{4 m/s-0m/s}{0.11 s}=36.4 m/s^2
If substitute the acceleration into the first equation, we find the distance covered by the fish:
S= \frac{1}{2}at^2= \frac{1}{2}(36.4 m/s^2)(0.11 s)^2=0.22 m

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As more resistors are added in series across a constant voltage source, the power supplied by the source: A) does not change. B)
Anon25 [30]

As series resistors are added, the resistance is added directly so the total resistance will be equal to

R_T = R_1+R_2+R_3... R_{\infty}

Since the power is determined as

P = \frac{V^2}{R}

We have there that

P \propto \frac{1}{R}

The power is inversely proportional to the increase in resistance, so it will tend to decrease as more resistors are added in series.

The correct answer is: C.

4 0
3 years ago
You are a member of a geological team in Central Africa. Your team comes upon a wide river that is flowing east. You must determ
Dovator [93]

Answer:

(a). The width of the river is 90.5 m.

The current speed of the river is 3.96 m.

(b). The shortest time is 15.0 sec and we would end 59.4 m east of our starting point.

Explanation:

Given that,

Constant speed = 6.00 m/s

Time = 20.1 sec

Speed = 9.00 m/s

Time = 11.2 sec

We need to write a equation for to travel due north across the river,

Using equation for north

v^2-c^2=\dfrac{w^2}{t^2}

Put the value in the equation

6.00^2-c^2=\dfrac{w^2}{(20.1)^2}

36-c^2=\dfrac{w^2}{404.01}....(I)

We need to write a equation for to travel due south across the river,

Using equation for south

v^2-c^2=\dfrac{w^2}{t^2}

Put the value in the equation

9.00^2-c^2=\dfrac{w^2}{(11.2)^2}

81-c^2=\dfrac{w^2}{125.44}....(II)

(a). We need to calculate the wide of the river

Using equation (I) and (II)

45=\dfrac{w^2}{125.44}-\dfrac{w^2}{404.01}

45=w^2(0.00549)

w^2=\dfrac{45}{0.00549}

w=\sqrt{\dfrac{45}{0.00549}}

w=90.5

We need to calculate the current speed

Using equation (I)

36-c^2=\dfrac{(90.5)^2}{(20.1)^2}

36-c^2=20.27

c^2=20.27-36

c=\sqrt{15.73}

c=3.96\ m/s

(b). We need to calculate the shortest time

Using formula of time

t=\dfrac{d}{v}

t=\dfrac{90.5}{6}

t=15.0\ sec

We need to calculate the distance

Using formula of distance

d=vt

d=3.96\times15.0

d=59.4\ m

Hence, (a). The width of the river is 90.5 m.

The current speed of the river is 3.96 m.

(b). The shortest time is 15.0 sec and we would end 59.4 m east of our starting point.

3 0
3 years ago
The number of protons in the nucleus is the number of blank
Tresset [83]
The number of protons in an atom identifies the Atomic Number
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6 0
3 years ago
Cindy runs 2 kilometers every morning. She takes 2 minutes for the first 250 meters, 4 minutes for the next 1,000 meters, 1 minu
PIT_PIT [208]

Answer:

200 m / min

Explanation:

Total distance = 2000 m

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Average speed = 2000 m / 10 min = 200 m/min

7 0
2 years ago
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