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ICE Princess25 [194]
3 years ago
5

" when striking, the pike, a predatory fish, can accelerate from rest to a speed of 4.0 m/s in 0.11 s."

Physics
1 answer:
Kipish [7]3 years ago
4 0
In an uniform accelerated motion, the distance covered by the fish is given by:
S= \frac{1}{2}at^2
where
a is the acceleration
t is the time

The acceleration is equal to the increase in speed of the fish divided by the time taken:
a= \frac{v_f-v_i}{t}= \frac{4 m/s-0m/s}{0.11 s}=36.4 m/s^2
If substitute the acceleration into the first equation, we find the distance covered by the fish:
S= \frac{1}{2}at^2= \frac{1}{2}(36.4 m/s^2)(0.11 s)^2=0.22 m

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What is the most appropriate SI unit to express the speed of a cyclist in a 10-km race? km/s cm/h km/h mm/s
Murljashka [212]
You sure wouldn't want something like cm/s or (yikes cm/hr). You want a reasonable number for sports usually between 0 and 100

Km / hour would be a good choice.

The next town to where I live is 25 km away. On a good day, I can make it there in about 3/4 of an hour.

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5 0
3 years ago
Two balls, each with a mass of 0.890 kg, exert a gravitational force of 8.06 × 10−11 n on each other. how far apart are the ball
Bond [772]
This problem involves Newton's universal law of gravitation and the equation to follow would be.

F = GM₁M₂/r²  

Given: M₁ = 0.890 Kg;  M₂ = 0.890 Kg;  F = 8.06 x 10⁻¹¹ N; G = 6.673 X 10⁻¹¹ N m²/Kg²

Solving for distance r = ?

r = √GM₁M₂/F

r = √(6.673 x 10⁻¹¹ N m₂/Kg²)(0.890 Kg)(0.890 Kg)/ 8.06 x 10⁻¹¹ N

r = 0.81 m 
6 0
3 years ago
4 Points
lbvjy [14]

Answer:

Impulse = 322.5[kg*m/s], the answer is D

Explanation:

This method  it is based on the principle of momentum and the amount of movement; and  used to solve problems involving strength, mass, speed and time.

If units of the SI are used, the magnitude of the impulse of a force is expressed in N * s. however, when remembering the definition of the newton.

N*S=(kg*m/s^{2} )*s = kg*m/s

Now replacing the values on the following equation that express the definition of impulse

Impulse = Force * Time\\\\Impulse = 215 * 1.5 = 322.5 [kg*m/s]

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<span>fast-moving particles colliding with slow-moving particles</span>
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