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mel-nik [20]
3 years ago
8

Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia

de potencial de 120 V, durante 18 minutos ¿Qué cantidad de calor produce?, expresado en calorías
Physics
1 answer:
Gala2k [10]3 years ago
5 0

Answer:

Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia de potencial de 120 V, durante 18 minutos ¿Qué cantidad de calor produce?, expresado en calorías

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Whenever you push an object across a frictional surface, it starts out taking a lot of force to push to get the object moving. H
son4ous [18]

Answer:

The answer is A

Explanation:

Here's an example. A child is in school taking a test. They have made a mistake on a question, and want to erase it. The eraser is made out of a type of rubber, the rubber has friction, which means the eraser has something that's going to resist movement. Now the child has exerted enough force to get it moving, and it's moving, it won't stop unless the child stops exerting force to keep it moving. Both Newton's 1st and 3rd law explain the action of moving something on a surface with friction.

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3 years ago
- What do the objects not in motion have in common?​
Semenov [28]

Answer:

they have zero velocity

Explanation:

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4 years ago
Electrons are BLANK<br> not Blank <br> -lonic Bond
DerKrebs [107]

Answer:

electrons are NEGATIVE not POSITIVE ionic bond

Explanation:

4 0
4 years ago
A 92.0-kg skydiver falls straight downward with an open parachute through a vertical height of 325 m. The skydiver’s velocity re
Alborosie

Answer:

The work done is 293.0kJ

Explanation:

<u>Data</u>

  • Mass:   m=92.0kg
  • height:    h=325m
  • acceleration due to gravity:  g=9.81m/s^{2}

Non conservative force act

The work is:

W=ΔKE+ΔPE

KE and PE means kinetic energy and potential energy respectively.

The change in kinetic energy is 0, since the skydiver’s velocity remains constant.

Therefore

W=0+ΔPE

W=ΔPE

W=mgh

substitute the values

W=92.0kg*9.81m/s^{2} *325m\\W=293020J\\W=293.0kJ

5 0
4 years ago
Wind gusts create ripples on the ocean that have a wavelength of 2.23 cm and propagate at 4.12 m/s. What is their frequency (in
stellarik [79]

Answer:

The frequency of the wave is 184.75 Hz.

Explanation:

Given;

wavelength of the wind, λ = 2.23 cm = 0.0223 m

speed of the wind wave, v = 4.12 m/s

the frequency of the wave = ?

The frequency of the wave is calculated as;

F = V / λ

Where;

F is the frequency of the wave

Substitute the given values and solve for F

F = (4.12) / (0.0223)

F = 184.75 Hz.

Therefore, the frequency of the wave is 184.75 Hz.

8 0
3 years ago
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