Answer:
equilibrium position.
Explanation:
In simple harmonic motion , velocity v(t) is given by,
v(t) = -ω A sin(ωt + φ)
where
ω = angular velocity of the corresponding circular motion
A = amplitude
t = time
φ = the initial angle of the corresponding circular motion when the motion begin.
v (t) get maximized when sin value is maximized , i.e. sin =1
The particle has maximum speed when it passes through the equilibrium position.
Answer:
<h2>15m/s</h2>Explanation:
The equation for a traveling wave as expressed as y(x, t) = A cos(kx − t) where An is the amplitude f oscillation,
is the angular velocity and x is the horizontal displacement and y is the vertical displacement.
From the formula; where;
Before we can get the transverse speed, we need to get the frequency and the wavelength.
frequency = 1/period
Given period = 2/15 s
Frequency =
frequency = 1 * 15/2
frequency f = 15/2 Hertz
Given wavelength = 2m
Transverse speed
Hence, the transverse speed at that point is 15m/s