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vredina [299]
3 years ago
9

For a spring oscillating in simple harmonic motion, at what point will the velocity of

Physics
1 answer:
Crazy boy [7]3 years ago
6 0

Answer:

equilibrium position.

Explanation:

In simple harmonic motion , velocity v(t) is given by,

v(t) = -ω A sin(ωt + φ)

where

ω = angular velocity of the corresponding circular motion

A = amplitude

t = time

φ = the initial angle of the corresponding circular motion when the motion begin.

v (t) get maximized when sin value is maximized , i.e. sin \alpha=1

The particle has maximum speed when it passes through the equilibrium position.

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Is bleach heterogeneous
irga5000 [103]
No, bleach is not heterogeneous. Bleach is actually homogeneous. 
Heterogeneous is if it the same throughout. 
Homogeneous is if it is different (has chunks and clumps of different materials)
6 0
3 years ago
A carpenter is driving a 15.0-g steel nail into a board. His 1.00-kg hammer is moving at 8.50 m/s when it strikes the nail. Half
bekas [8.4K]

Answer: The increase in temperature of the nail after the three blows is 8.0636 Kelvins. The correct option is (d).

Explanation:

Kinetic energy of the hammer ,K.E.=

\frac{1}{2}mv^2=\frac{1}{2}1.00 kg\times (8.50 m/s)^2=36.125 J

Half of the kinetic energy of the hammer is transformed into heat in the nail.

Energy transferred to the nail in one blow =

\frac{1}{2}K.E.=\frac{1}{2}\times 36.125 J=18.0625 J

Total energy transferred after 3 blows,Q =3\times 18.0625 J=54.1875 J

Mass of the nail = 15 g = 0.015 kg

Change in temperature =\Delta T

Specif heat of the steel = c = 448 J/kg K

Q=mc\Delta T

54.1875 J=0.015 kg\times 448 J/kg K\times \Delta T

\Delta T=8.0636 K\approx 8.1 K

The increase in temperature of the nail after the three blows is 8.1  Kelvins.Hence, correct option is (d).

4 0
3 years ago
What are the Rules of magnetism
Keith_Richards [23]

all the allials must be aligned in the same direction

magnets are affected by heat, drops, and improper storage

3 0
3 years ago
An object is five focal lengths from a concave mirror.how do the object and image heights compare?
enot [183]

An object distance is presented as s = 5f and we know that the mirror equation relates the image distance to the object distance and the focal length.

The mirror equation is 1/f = 1/s + 1/s’ where the variable f stands for the focal length of the mirror. Variable (s) represents the distance between the mirror surface and the object and the variable <span>(s’) represents the distance between the mirror surface and the image. </span>

In addition, a concave mirror will have a positive focal length (f) and a convex mirror will have a negative focal length (f).

Now, we then have 1/f = 1/5f + 1/s’ which is s’ = 5f/4

Then we get the magnification ratio that expresses the size or amount of magnification or reduction of the object or image and to get the magnification, we use this equation: M= s’/s

M= 5f/4x5f

s’ = 1/4s

Therefore, the image height is one fourth of the object height

7 0
3 years ago
Pls answer quick will mark brainlest and 5 stars
QveST [7]

Answer:A

Explanation:

It’s bigger I am not sure

7 0
3 years ago
Read 2 more answers
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